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3 years ago

How much energy is converted when a 110kw appliance is used for 3.0 hrs?

Physics

1 answer:

nadya68 [22]3 years ago

8 0

https://quizlet.com/latest

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A cell of internal resistance 2 ohms supplies current to a 6 ohms resistor. What is the efficiency of the cell?.

Margaret [11]

75% is the efficiency of the cell.

Explanation:

Internal resistance is the resistance generated due to the devices present in the circuit. Most preferably, it is the resistance of the battery connected to the circuit.

As the current, resistance of the resistor and the internal resistance of the battery is given as 6 A, 6 ohms and 2 ohms.

Then the efficiency of the cell is $E = \frac{IR}{I (R+r)} =\frac{R}{r+R}$

So, the efficiency of the cell is $E=\frac{R}{r+R}$

Then, E = $\frac{6}{2+6}=\frac{6}{8}$

So, the efficiency is 75%.

75% is the efficiency of the cell.

4 0

3 years ago

174cm=____ m<br>1.74<br>17.4<br>1740<br>17,400

FinnZ [79.3K]

Correct answer is 1.74cm

5 0

4 years ago

A 8.10×10^3 ‑kg car is travelling at 25.8 m/s when the driver decides to exit the freeway by going up a ramp. After coasting 3.9

KengaRu [80]

Answer:

The magnitude of the average drag force is 2412.34 N.

Explanation:

Given that,

Mass of car $m=8.10\times10^{-3}\ kg$

Velocity v = 25.8 m/s

Distance $d= 3.90\times10^{2}$

Speed of car = 13.1 m/s

Height = 12.5 m

We need to calculate the magnitude of the average drag force

Using equation kinetic energy

$K.E_{i}=K.E_{f}+P.E+F_{d}$

$\dfrac{1}{2}mv_{i}^2=\dfrac{}{}mv_{f}^2+mgh+F\times d$

Where, $v_{i}$ = initial velocity

$v_{f}$ = final velocity

h = height

g = acceleration due to gravity

$F_{d}$ =drag force

m = mass of the car

d = distance

Put the value into the formula

$\dfrac{1}{2}\times8.10\times10^{3}\times25.8=\dfrac{1}{2}\times8.10\times10^{3}\times13.1+8.10\times10^{3}\times9.8\times12.5+F\times3.90\times10^{2}$

$F=\dfrac{\dfrac{1}{2}\times8.10\times10^{3}\times25.8-\dfrac{1}{2}\times8.10\times10^{3}\times13.1-8.10\times10^{3}\times9.8\times12.5}{3.90\times10^{2}}$

$F=-2412.34\ N$

$|F|=2412.34\ N$

Hence, The magnitude of the average drag force is 2412.34 N.

4 0

4 years ago

a crate is being lifted into a truck. if it is moved with a 2470n force and 3650 j of work is done , then how far is the crate b

SVEN [57.7K]

Answer:

The crate was being lifted by a height of 1.48 meters.

Explanation:

In an attempt o move a crate;

Force applied = 2470 N

Work done by the force = 3650 J

We know that the work done is defined as the force used to move an object to a distance.

Given the Force used and the work done by that Force, we need to find out the distance the crate was lifted to.

Work done is defined as:

Work = Force*distance covered in the direction of the force

3650 = 2470*distance

distance = 3650/2470

distance = 1.48 meters

4 0

3 years ago

A circuit contains a single 220 pF capacitor hooked across a battery. It is desired to store three times as much energy in a com

Anettt [7]

Answer

The capacitor should be connected in parallel as parallel connection gives the arithmetic sum of capacitance which will give a corresponding sum of energy while capacitors in series gives the sum of the reciprocal if the individual capacitance

7 0

4 years ago