Explain why the helium gas inside this balloon exerts pressure on the balloon.
1 answer:
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Answer:
negative acceleration of 4m/s²
Explanation:
Given parameters:
Initial velocity = 66m/s
Final velocity = 26m/s
Time taken = 10s
Unknown:
Description of the acceleration = ?
Solution:
Acceleration is the rate of change of velocity with time.
It is mathematically expressed as;
acceleration =
v is the final velocity
u is the initial velocity
t is the time taken
Now insert the parameters and solve;
Acceleration = = -4m/s²
So, we see a negative acceleration of 4m/s²
Answer:
The anserrs to the question are
(a) The temperature would be 566.67 K and
(b) The pressure of the resulting air stream is 14 bar
Explanation:
Here the two streams of gases meet ad form a single stream
The steady-flow energy equation can be implemented at the mixing point of the to streams as follows
mₐhₐ₁ + mₙ hₙ₁ + Q° + W° = mₐhₐ₂ + mₙhₙ₂
Where the flow is adiabatic, we have
Q = 0 and W = 0 hence
mₐhₐ₁ + mₙ hₙ₁ = mₐhₐ₂ + mₙhₙ₂ where h = cp×T we have
mₐcpₐ×Tₐ + mₙcpₙ×Tₙ = mₐcpₐ×T + mₐcpₙ×T
Therefore the final temperature T is given by
for the same kind of gas cpₐ =cpₙ therefore
where mₐ and mₙ are mass flow rate
Therefore we have where Tₐ = = 900 K and Tₙ = 400 K and mₙ = 2mₐ gives
=
= 1700/3 = 566.67 K
From Dalton's law, the total pressure of a mixture of gases is equal to the sum of the partial pressures of the components of the mixture
Therefore the total pressure of the combined stream = pₐ + pₙ = p
= 12 bar + 2 bar = 14 bar
Stream pressure = 14 bar
Answer:
W(r,out) = 5.81 MW
= 86.1 %
Explanation:
we use here steam table for get value of h1, s1 etc
so use for 6MPa and 600 degree
Enthalphy of steam h1 = 3658.8 kJ/kg
Entropy of steam s 1 is = 7.1693 kJ /kg.K
and
for 50 kPa and 100 degree
Enthalphy of steam h2 = 2682.4 kJ/kg
Entropy of steam s2 is = 7.6953 kJ /kg.K
so we use here energy balance equation that is
..............1
put here value and we get m
m =
solve it we get
m = 5.156 kg/s
so by energy balance equation
m1 = m
2 + W(r,out)
W(r,out) = m(1 -
2)
W(r,out) = h1 - h2 + ΔKE + ΔPE - To(s1-s2)
W(r,out) =
W(r,out) = W(a,out) - m.To.(s1-s2) ........................2
put here value
W(r,out) = 5000 - ( 5.156 × (25 + 273) ×( 7.1693 - 7.6953)
W(r,out) = 5908.19 = 5.81 MW
and
second law deficiency is
=
..............................3
put here value
= \frac{5}{5.81}
= 86.1 %