Explanation:
The journal entry is as follows
Notes receivable A/c Dr $11,100
To Sales A/c $11,100
(Being the sales is recorded)
Since the merchandise transaction is done through note receivable so we debited the note receivable account and the transaction is of sale type so the sales account is credited. Both the transactions are recorded at $11,100
Answer: • provide a permanent record for the cost of goods sold account
• monitor costs incurred to date and to predict and control costs for each job.
• provide a subsidiary ledger for the finished goods inventory account.
Explanation:
Job cost sheet refers to the document that is used for the recording of the manufacturing costs and it is used as a subsidiary ledger for the work in process account due to the fact that it contains every details about the job in process.
From the options given, the job cost sheets can be used to:
• provide a permanent record for the cost of goods sold account
• monitor costs incurred to date and to predict and control costs for each job.
• provide a subsidiary ledger for the finished goods inventory account.
Answer:
C. disposing of long minus lived assets for non cash proceeds
Explanation:
As we know that
Cash flow statement deals with the cash inflow and cash outflow of cash payments which increase or decrease the cash balance.
In another words, the inflow of cash increases the cash balance whereas the outflow of cash is decreases the cash balance
It includes operating activities, investing activities, and the financing activities.
Since all the given options includes the cash transactions except c.
Answer:
the minimum price it should charge is $40 per unit.
Explanation:
Minimum Transfer Price = Variable Costs - Internal Savings + Opportunity Cost
<em>Note : Division A has capacity available to meet B's requirements therefore there is no opportunity cost</em>.
There are Internal savings of $5 as A's variable costs will be $5 less per unit.
Minimum Transfer Price = $45 - $5
= $40
Answer:
Final Value= $61,037.04
Explanation:
Giving the following information:
Investment= $2,378 in a bank at the end of every year for 10 years.
The company makes no deposits during the subsequent 5 years.
Interest rate= 10%
First, we need to calculate the first 10 years.
FV= {A*[(1+i)^n-1]}/i
A= annual deposit
FV= {2,378*[(1.1^10)-1]} / 0.1
FV= $37,899.20
Now, the 5 years:
FV= PV*(1+i)^n
FV= 37,899.2*(1.1^5)
FV= $61,037.04
