El área superficial total de los veinte tarugos es mayor que el área superficial cubierta por el pegamento.
<h3>Como determinar si la superficie cubierta por el pegamento es suficiente</h3>
En esta pregunta debemos calcular el área superficial total de los tarugos (
), en milímetros cuadrados, y comparar el resultado con la cifra afirmada por Eduardo. El área superficial total es:
En consecuencia, el área superficial total de los veinte tarugos es mayor que el área superficial cubierta por el pegamento. Francisca tiene la razón. 
<h3>Observación</h3>
El enunciado omite las dimensiones <em>geométricas</em> de cada tarugo (5 milímetros de radio y 80 milímetros de longitud).
Para aprender más sobre áreas, invitamos cordialmente a ver esta pregunta verificada: brainly.com/question/391394
Answer:
0.34134
Step-by-step explanation:
In other to solve for this question, we would be using the z score formula
z = (x - μ) / σ
x = raw score
μ = mean
σ = Standard deviation
We are told in the question to find the probability that a worker selected at random makes between $350 and $400
let x1 = 350 and x2= 400 with the mean μ = 400 and standard deviation σ = $50.
z1 = (x1 - μ) / σ = (350-400) / 50 = -1
z2 = (x2 - μ) / σ = (400 - 400) / 50 = (0/50) = 0
From tables, P(z <= -1) = 0.15866
P(z <= 0) = 0.5
Then, the probability would give us, P(-1 ≤ z ≤ 0) =0.5 - 0.15866 =
0.34134
Hence, The probability that a worker selected at random makes between $350 and $400 = 0.34134
Answer:
Tim read 81 pages.
Step-by-step explanation:
If he read 3 pages on Monday and tripled the amount of pages he red based of off the amount of pages he read the previous day, he would have read 3 pages on Monday, 9 pages on Tuesday, 27 pages on Wednesday, and 81 pages on Thursday.
Monday: 3
Tuesday: 3 x 3 = 9
Wednesday: 9 x 3 = 27
Thursday: 27 x 3 = 81
I hope this helps you! :D
100 times (6+5)
100 times 11
100 groups of 11=1100
Hope I helped:)
Answer:
<h2>
Step-by-step explanation:</h2><h2>|(5x-4)-3|<0.01</h2><h2>so -0.01<(5x-4-3)<0.01</h2><h2>add 7</h2><h2>7-0.01<5x<7+0.01</h2><h2>6.99<5x<7.01</h2><h2>divide by 5</h2><h2>1.398<x<1.402</h2>
