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Sauron [17]
3 years ago
13

50.0 mL of an HNO^3 solution were titrated with 36.90 mL of a 0.100 M LiOH solution to reach the equivalence point. What is the

Molarity of the HnO^3 solution. But the threes are on the low right corner
Chemistry
1 answer:
NISA [10]3 years ago
6 0

Answer:

0.0738 M

Explanation:

HNO3 +LiOH = LiNO3 + H2O

Number of moles HNO3 = number of moles LiOH

M(HNO3)*V(HNO3) = M(LiOH)*M(LiOH)

M(HNO3)*50.0mL = 0.100M*36.90 mL

M(HNO3) = 0.100*36.90/50.0 M = 0.0738 M

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A 28.5 gram piece of iron is added to a graduated cylinder containing 45.5 mL of water. The water in the cylinder rises to the 4
sweet-ann [11.9K]

Answer:

7.92 .g . mL^-1

Explanation:

Data provided in the question

Water liters = 45.5 mL

Pace of iron = 28.5 gram

Rise in the water in the cylinder = 49.1 mark

So by considering the above information

As we know that

Density = \frac{Mass}{Volume}

where,

Mass = 28.5 gram

Volume = 49.1 - 45.5

              = 3.6 mL

So, the density is

Density = \frac{28.5}{3.6}

= 7.92 .g . mL^-1

Basically we use the density formula by dividing the mass with the volume

4 0
3 years ago
How many electrons are present in the nonbonding π molecular orbital of the allyl anion? a. 2 b. 1 c. 3 d. 0
Nostrana [21]

The number of electrons, which are present in the nonbonding π molecular orbital of the allyl anion is "0".

Anions, cations, but also allylic radicals have always been frequently mentioned as reaction intermediates. Each one has three adjacent sp^{2}-hybridized carbon centers, and they all rely on resonance for stability. Two resonance structures would be used to present each species, with the charge as well as unpaired electron scattered across both the 1,3 and 0 positions.

The Aufbau principle states that these orbitals would fill up based on the order of stability, therefore a typical pi bond, will have 2 electrons in the Pi orbital as well as zero in the Pi* orbital.

Therefore, the correct answer will be option (d)

To know more about allyl anion

brainly.com/question/14286167

#SPJ4

6 0
2 years ago
Classify the following reactions into: Element – Element, Element – Compound, Compound – Compound
Rudiy27

Answer:

1. CaO + H₂O ----> Ca(OH)₂

Compound ----- Compound

2. 2 Na + Cl₂ ----> 2 NaCl

Element ----- Element

3. 2 SO₂ + O₂ ----> 2 SO₃

Element ----- Compound

3 0
2 years ago
Which substance could any excess not be removed by filtration​
horrorfan [7]

Answer:

sodium hydroxide

Explanation:

i think sodium hydroxide

6 0
3 years ago
A student prepares a 0.47mM aqueous solution of acetic acid CH3CO2H. Calculate the fraction of acetic acid that is in the dissoc
Aliun [14]

The fraction of acetic acid that is dissociated is 0.18

Why?

The chemical equation for the dissociation of acetic acid (HAc) is the following:

HAc(aq) + H₂O(l) ⇄ H₃O⁺(aq) + Ac⁻(aq)

To find the fraction of acetic acid that is in the dissociated form (f), we apply the following equation (Ka for acetic acid is 1.76*10⁻⁵). This equation comes from solving the equation of the equilibrium constant for the dissociated fraction of HAc:

f=\frac{-Ka+\sqrt{Ka^{2} +4KaC} }{2C} = 0.18

Have a nice day!

#LearnwithBrainly

6 0
3 years ago
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