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ivolga24 [154]
3 years ago
10

Determine whether the bonds in CCl4 and N2 are polar or non-polar. If the bond is polar, assign the partial positive and negativ

e charges. Electronegativity values: C = 2.5, Cl= 3.0, N= 3.0
Chemistry
1 answer:
stira [4]3 years ago
7 0

Refer to the attachment

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How many grams of carbon are contained in one mole of<img src="https://tex.z-dn.net/?f=C_%7B3%7DH_%7B8%7D" id="TexFormula1" titl
NNADVOKAT [17]

\quad \huge \quad \quad \boxed{ \tt \:Answer }

\qquad \tt \rightarrow \:36 \:\: g

____________________________________

\large \tt Explanation \: :

The given compound has 3 carbon atoms, so in 1 mole of that compound, there will be 3 moles of carbon atoms.

Mass of each mole of carbon atoms = 12 g

For 3 mole carbon atoms, it will be 12 × 3 = 36 grams

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

4 0
2 years ago
The matter through which waves travel is called a/an​
sweet [91]

Answer:

A medium.

<h3>Explanation:</h3>

It's the material the wave is travelling through.

5 0
3 years ago
Why is copper (i) sulfate Cu2So4^-2? not copper (ii)?
const2013 [10]
Copper (I) oxidation state is 1 Cu2So4
copper (II) oxidation state is +2 CuSo4
copper (i) also give up one electron so you need two of them to react with the sulfate ion (which has charge of -2)
and also all metallic ions have an multiple oxidation levels corresponding to the number of electrons they can exchange or loose
Hope this helps
5 0
3 years ago
Read 2 more answers
What is an example of entropy from everyday life?
Lorico [155]
One of the greatest examples of entropy working in everyday life is the fact that a messy room is the norm. So if you clean your room it will likely become messy over a period of time, and work will have to be put in to make it orderly again.
4 0
3 years ago
The freezing point of ethanol, CH3CH2OH, is -117.300 °C at 1 atmosphere. Kf(ethanol) = 1.99 °C/m
MAXImum [283]

Answer : The molecular weight of this compound is 891.10 g/mol

Explanation :  Given,

Mass of compound = 12.70 g

Mass of ethanol = 216.5 g

Formula used :  

\Delta T_f=i\times K_f\times m\\\\T_f^o-T_f=i\times T_f\times\frac{\text{Mass of compound}\times 1000}{\text{Molar mass of compound}\times \text{Mass of ethanol}}

where,

\Delta T_f = change in freezing point

T_f^o = temperature of pure ethanol = -117.300^oC

T_f = temperature of solution = -117.431^oC

K_f = freezing point constant of ethanol = 1.99^oC/m

i = van't hoff factor = 1   (for non-electrolyte)

m = molality

Now put all the given values in this formula, we get

(-117.300)-(-117.431)=1\times 1.99^oC/m\times \frac{12.70g\times 1000}{\text{Molar mass of compound}\times 216.5g}

\text{Molar mass of compound}=891.10g/mol

Therefore, the molecular weight of this compound is 891.10 g/mol

7 0
3 years ago
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