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Vanyuwa [196]
3 years ago
7

A runner completes the 300 meter dash in 38 seconds what is the speed of the runner? Round your answer to the nearest tenth

Physics
2 answers:
VMariaS [17]3 years ago
8 0

Answer:

7.9 is the correct answer.

Explanation:

grandymaker [24]3 years ago
7 0
38 = 300
60 = ?
300 × 60 ÷ 38
1800 ÷ 38 = 47.368
The answer is 47.4 m per hour
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The volume of liquid flowing per second is called the volume flow rate Q and has the dimensions of [L]3/[T]. The flow rate of li
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Answer: n=4

Explanation:

We have the following expression for the volume flow rate Q of a hypodermic needle:

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We need the right side of the equation to be equal to the left side of the equation (in dimensions):

\frac{L^{3}}{T}=\frac{\pi}{8} \frac{ L^{n}}{LT}  (3)

\frac{L^{3}}{T}=\frac{\pi}{8} \frac{ L^{n-1}}{T}  (4)

As we can see n must be 4 if we want the exponent to be 3:

\frac{L^{3}}{T}=\frac{\pi}{8} \frac{ L^{4-1}}{T}  (5)

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In her hand, a softball pitcher swings a ball of mass 0.245 kg around a vertical circular path of radius 59.8 cm before releasin
GuDViN [60]

Answer:

The velocity is v_b = 20.17 \ m/s

Explanation:

From the question we are told that

   The mass of the ball is  m = 0.245 \ kg

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   The speed of the ball is  v = 16.0 \ m/s.

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    K_t  =  \frac{1}{2} *  m  *  v^2

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Generally the work done by the force applied on the ball from the top to the bottom  is mathematically represented as

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       d =  \pi * r

So

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Generally the kinetic energy at the bottom is mathematically represented as

      K_b  =  \frac{1}{2} *  m *  v_b^2

=>    K_b  =  \frac{1}{2} *  0.245  *  v_b^2

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