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Yuki888 [10]
3 years ago
7

6. On a quiet day, the atmospheric pressure results in a force of about 10,0000 N on a window pane with an area of 1 square mete

r. a. Why does this large force not shatter the window? b. How will this change if a strong wind is blowing across the window pane?
Physics
1 answer:
kherson [118]3 years ago
6 0

Explanation:

a. The same atmospheric pressure that's pushing the window from the outside is also pushing on the window from the inside.  So the forces are balanced.

b. If a strong wind is blowing <em>across</em> the window pane, the pressure will drop, as described by the Bernoulli principle.  So the pressure inside will be greater than the pressure outside, causing the window to bow out a little.

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Why would an egg break immediately when it hits the ground?
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Sam is playing football. She kicks the ball with an average force of 75 N.
damaskus [11]

Answer:

22.5J

Explanation:

Here the force is given. Also, the displacement is given as 30cm.

First we should check if all the values are in their standard form.

Here 30cm should be converted to metre by dividing it with 100.

Which would give us 0.3m

Now we use the equation W=force x displacement =75 x 0.3=22.5J

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3 years ago
You apply a potential difference of 5.70 v between the ends of a wire that is 2.90 m in length and 0.654 mm in radius. the resul
photoshop1234 [79]
1) First of all, let's find the resistance of the wire by using Ohm's law:
V=IR
where V is the potential difference applied on the wire, I the current and R the resistance. For the resistor in the problem we have:
R= \frac{V}{I}= \frac{5.70 V}{17.6 A}=0.32 \Omega

2) Now that we have the value of the resistance, we can find the resistivity of the wire \rho by using the following relationship:
\rho =  \frac{RA}{L}
Where A is the cross-sectional area of the wire and L its length.
We already have its length L=2.90 m, while we need to calculate the area A starting from the radius:
A=\pi r^2 = \pi (0.654\cdot 10^{-3}m)^2=1.34 \cdot 10^{-6}m^2

And now we can find the resistivity:
\rho =  \frac{RA}{L}= \frac{(0.32 \Omega)(1.34 \cdot 10^{-6}m^2)}{2.90m}=  1.48 \cdot 10^{-7}\Omega \cdot m
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3 years ago
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