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Cerrena [4.2K]
3 years ago
6

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Physics
1 answer:
Sedaia [141]3 years ago
6 0

Answer:

V = 20.5 m/s

Explanation:

Given,

The mass of the cart, m = 6 Kg

The initial speed of the cart, u = 4 m/s

The acceleration of the cart, a = 0.5 m/s²

The time interval of the cart, t = 30 s

The final velocity of the cart is given by the first equation of motion

                              v = u + at

                                  = 4 + (0.5 x 30)

                                = 19 m/s

Hence the final velocity of cart at 30 seconds is, v = 19 m/s

The speed of the cart at the end of  3 seconds

                                    V = 19 + (0.5 x 3)

                                       = 20.5 m/s

Hence, the final velocity of the cart at the end of this 3.0 second interval is, V = 20.5 m/s

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Answer:

\frac{\pi }{15}m

Explanation:

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= 60°

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The positive charge (of the same value) on the external surface of the conducting shell is:

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4 years ago
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Answer:

Following are the answer to this question:

Explanation:

In option (a):

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In option (b):

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