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3 years ago

8

A car travels 50km in 2 hours.

1 answer:

ser-zykov [4K]3 years ago

3 0

Answer: it will travle 25km pr hour

Explanation:

sevide both by 2

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All of the following are functions of the skeletal system EXCEPT:

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| A T-ball with a mass of 0.6 kg travels in the

r-ruslan [8.4K]

Answer:

$|I|=6\ Kg.m/s$

$F=120\ N$

Explanation:

Impulse and Momentum

They are similar concepts since they deal with the dynamics of objects having their status of motion changed by the sudden application of a force. The momentum at a given initial time is computed as

$p_o=m.v_o$

When a force is applied, the speed changes to $v_1$ and the new momentum is

$p_1=m.v_1$

The change of momentum is

$\Delta p=p_1-p_0=m(v_1-v_o)$

The impulse is equal to the change of momentum of an object and it's defined as the average net force applied times the time it takes to change the object's motion

$I=F.t=\Delta p$

Part 1

The T-ball initially travels at 10 m/s and then suddenly it's stopped by the glove. The final speed is zero, so

$\Delta p=0.6\ Kg(0-10\ m/s)=-6\ Kg.m/s$

The impulse is

$I=\Delta p$

$I=-6\ Kg.m/s$

The magnitude is

$|I|=6\ Kg.m/s$

Part 2

The force can be computed from the formula

$I=F.t$

The direction of the impulse the T-ball receives is opposite to the direction of the force exerted by the ball on the glove, thus $I_b=6\ kg.m/s$

$\displaystyle F=\frac{I}{t}=\frac{6\ kg.m/s}{0.05\ s}$

$\boxed{F=120\ N}$

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3 years ago

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2 years ago

Based on experimental observations, the acceleration of a particle is defined by the relation a = -(0.1 + sin x/b), where a and

Fiesta28 [93]

Answer:

Velocity,v = 0.323 m/s

Explanation:

The acceleration of a particle is given by :

$a=-(0.1+sin\dfrac{x}{b})$

b = 0.8 m when x = 0

Since, $a=v\dfrac{dv}{dx}$

$v\dfrac{dv}{dx}=-(0.1+sin\dfrac{x}{b})$

$\int{v.dv}=\int{-(0.1+sin\dfrac{x}{b})}.dx$

$\dfrac{v^2}{2}=-[0.1x-0.8cos\dfrac{x}{0.8}]+c$

At x = 0, v = 1 m/s

$\dfrac{1}{2}=0.8+c$

$c=-0.3$

$\dfrac{v^2}{2}=-[0.1x-0.8cos\dfrac{x}{0.8}]-0.3$

At x = -1 m

$\dfrac{v^2}{2}=-0.1(-1)+0.8cos\dfrac{(-1)}{0.8}-0.3$

${v^2}=0.1045$

v = 0.323 m/s

So, the velocity of the particle is 0.323 m/s. Hence, this is the required solution.

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As the ball rolls down the ramp, there are changes in kinetic and potential energy. How much kinetic energy does the ball have w

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Answer: C. 50j

Explanation:

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