Answer:
The magnitude of force must you apply to hold the platform in this position = 888.89 N
Explanation:
Given that :
Workdone (W) = 80.0 J
length x = 0.180 m
The equation for this work done by the spring is expressed as:
Making the spring constant 
the subject of the formula; we have:
Substituting our given values, we have:
The magnitude of the force that must be apply to the hold platform in this position is given by the formula :
F = 888.89 N
Answer:
we don't care what ure saying thats absurd
You need to divide the motion into its component: vertical and horizontal motion.
The time taken to fall vertically from the cliff is equal to the time taken to move horizontally.
Using the vertical component, which is an accelerated motion with an initial velocity equal to zero, we can solve for t:
h = 1/2 · g · t²
t = √(2·h / g)
= √(2·50 / 9.8)
= 3.2 s
Horizontally, it is a constant motion:
d = v · t
= 20 · 3.2
= 64 m
The ball will strike the ground at a distance of 64 meters from the cliff.
1 ampere is 1 coulomb of charge moving through a cross section in one second.
Answer:
electric flux = 177.625 N-m²/C
Explanation:
given data
angle = 45°
diameter = 4 m
electric field E = 20 N/C
to find out
electric flux
solution
we know electric flux formula that is
electric flux = E × A × cosθ ..............1
here A is area that is
Area = πd²/4 = π(4)²/4 = 12.56 m²
now put all value in equation 1
electric flux = 20 × 12.56 × cos45
electric flux = 177.625 N-m²/C
