Answer:
5 × 10¹⁰ or 5 billion times louder is the intensity of sound at a rock concert in comparison with that of a whisper
Explanation:
Given that at a rock concert;
the intensity of sound is 110 dB compared to a whisper of 3 dB
Now; how many times louder will that of the whisper be compared to the sound of the rock concert
Using the formula for calculating decibels (dB);
For 110 dB
dB = 10log₁₀(W)
110 dB = 
110 dB = 10¹¹
For 3dB
dB = 10log₁₀(W)
3 dB = 
3 dB = 2
Now:
(110/3)dB = 10¹¹/2
(110/3)dB = 5 × 10¹⁰ or 5 billion times louder is the intensity of sound at a rock concert in comparison with that of a whisper
Answer: increases
Explanation:
Because the relationship between hand d is counter
Answer:
The peak wavelength of the light it irradiates decreases
Explanation:
As the temperature of a blackbody increase, the peak wavelength of the light it radiates decreases, this follows Wien's Law.
A blackbody is an ideal substance that emits all frequencies of light and also has the ability to absorb them as well.
Wiens displacement law, explains that the position of the peak wavelength of the thermal radiation emitted by bodies can change with temperature, and as the temperature increases beyond a certain point, the wavelength begins to reduce. This often changes the colour of the light emitted from heated objects.
Answer:
D. 2.0 kg m/s
Explanation:
Momentum after = momentum before
p = (0.500 kg) (4.0 m/s) + (1.0 kg) (0 m/s)
p = 2.0 kg m/s
