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qwelly [4]
3 years ago
6

George is planning an experiment to see how fast different sized cans of soup can roll down a ramp in his kitchen. He will be ro

lling them down a ramp and them time how fast it take them to travel 1 meter after the ramp. As George's Lab partner, what would be an appropiate hypothesis for George's Experiment?
a
The heavier cans will be faster, because science
b
If the can is denser, then it will take less time to cross 1 m, because gravity made it go faster down the ramp
c
The denser the soup can gets, the faster it will go, because gravity.
d
If the can is heavier, it will roll faster down the ramp due to gravity.
Physics
1 answer:
ddd [48]3 years ago
6 0
If it were me, I would choose D.
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Tim's car breaks down just down the street from his house. he and his friends decide to try to push it to his house. using newto
daser333 [38]
Pushing a broke down car, even done by more than one person, is difficult especially if the distance to be covered is quite far. A car is heavy and it requires a lot of force to start the car moving. This is because the inertia of the car to remain at rest is great. Additionally, the force applied in pushing the car must be greater than the frictional force to cause it to accelerate. The frictional force is dependent on the mass of the object which means that the frictional force acting on the car is also great. Finally, with every push of the car, the frictional force will always be present and acting on the opposite direction. The push that will be supplied must be sustained all throughout.
6 0
3 years ago
Read 2 more answers
A 1.8 kg uniform rod with a length of 90 cm is attached at one end to a frictionless pivot. It is free to rotate about the pivot
Leokris [45]

Answer:

a. 32.67 rad/s²  b. 29.4 m/s²

Explanation:

a. The initial angular acceleration of the rod

Since torque τ = Iα = WL (since the weight of the rod W is the only force acting on the rod , so it gives it a torque, τ at distance L from the pivot )where I = rotational inertia of uniform rod about pivot = mL²/3 (moment of inertia about an axis through one end of the rod), α = initial angular acceleration, W = weight of rod = mg where m = mass of rod = 1.8 kg and g = acceleration due to gravity = 9.8 m/s² and L = length of rod = 90 cm = 0.9 m.

So, Iα = WL

mL²α/3 = mgL

dividing through by mL, we have

Lα/3 = g

multiplying both sides by 3, we have

Lα = 3g

dividing both sides by L, we have

α = 3g/L

Substituting the values of the variables, we have

α = 3g/L

= 3 × 9.8 m/s²/0.9 m

= 29.4/0.9 rad/s²

= 32.67 rad/s²

b. The initial linear acceleration of the right end of the rod?

The linear acceleration at the initial point is tangential, so a = Lα = 0.9 m × 32.67 rad/s² = 29.4 m/s²

5 0
3 years ago
A 35.8 kg box initially at rest is pushed 2.38 m along a rough, horizontal floor with a constant applied horizontal force of 108
tiny-mole [99]

Answer:

The work done by the applied force is 259.22 J.

Explanation:

The work done by the applied force is given by:

W = F*d

Where:

F: is the applied horizontal force = 108.915 N

d: is the distance = 2.38 m  

Hence, the work is:

W = F*d = 108.915 N*2.38 m = 259.22 J

Therefore, the work done by the applied force is 259.22 J.

I hope it helps you!                                                

6 0
3 years ago
Compute the work performed when 32 pounds is lifted 10 feet.
Murljashka [212]
W = force * displacement
W = 32 pounds * 10 feet
Now you need to convert it to newton and meters
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(I approximated the conversions- I hope it helps)
7 0
3 years ago
Which of the following best defines force
vlada-n [284]

The middle one on the list is the correct one.

The first one ... distance divided by time ... is Speed, not force.

The third one ... mass times velocity ... is Momentum, not force.

3 0
3 years ago
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