May I get some help? Thank you!
2 answers:
You might be interested in
Answer:
Fraction:
Decimal: 0.25
Percentage: 25%
Step-by-step explanation:
Have a good day :)
Complete Question:
ABCD Is a rectangle that represents a park.
The lines show all the paths in the park.
The circular path is in the centre of the rectangle and has a diameter of 15m.
Calculate the shortest distance from A to C across the park,using only the lines shown.
*See attachment for the diagram showing the paths in the park.
Answer:
Shortest distance from A to C through the paths only = 102.9 m
Step-by-step explanation:
Length of park = 80 m
Width of park = 50 m
Diameter of the circular path in the center of the park = 15 m
Therefore:
Shortest distance between from A to C across the park if we're to follow only the lines showing the oaths would be = (length of diagonal AC - diameter of the circular path) + (½ of the circumference of the circular path)
✔️Use pythagorean theorem to find AC:
AC = √(80² + 50²) = √8,900
AC = 94.3398113 ≈ 94.34 m (nearest hundredth)
✔️Diameter of circular path = 15 m
✔️½ of the circumference of the circular path = ½(πd)
d = 15 m
½ of the circumference = ½(π*15) = 23.5619449 ≈ 23.56 m (nearest hundredth)
✔️Shortest distance = (94.34 - 15) + 23.56 = 79.34 + 23.56 = 102.9 m
Answer:
y=-2+4
Step-by-step explanation:
we know the y intercept is four, so we can plug that into y=mx+b
so far we know y=mx+4
and the equation for finding slope is
so let's find two points on the graph
let's make it easy on ourselves and use the points laid out for us
(0,4) and (2,0)
solving that would come out to be
simplified, that would be -2
now that we know the slope, we can put them into slope-intercept form
y=-2+4