Answer:
we have τ = I * α as the rotational equation of motion
and we also have τ = F * r
so the torque τ = 5* 0.16 Nm = 0.8 Nm
from your plot of θ vs T^2 , calculate the slope of the line
this slope will be angular acceleration α.
Then you get I = τ/α
Explanation:
Answer:
golf course
Explanation:
i will give you all the answers you desire, my love
Answer:
This is what they said in english if everyone was wondering
Explanation:
determine the value of the velocity carried by a body whose mass is 3kg and its kinetic energy is 400Joule
Answer:
The kinetic energy of an electron is 
Explanation:
Given that,
Distance = 0.1 nm
We need to calculate the momentum
Using uncertainty principle
Where, 
= change in momentum
= change in position
Put the value into the formula
We need to calculate the kinetic energy for an electron
Where, P = momentum
m = mass of electron
Put the value into the formula
Hence, The kinetic energy of an electron is
Answer:
The time taken for the car to stop is 5.43 s.
The initial velocity of the car is 108.6 ft/s
Explanation:
The following data were obtained from the question:
Acceleration (a) = –20 ft/s² (since the car is coming to rest)
Distance travalled (s) = 295 ft
Final velocity (v) = 0 ft/s
Time taken (t) =?
Initial velocity (u) =?
Next, we shall determine the initial velocity of the car as shown below:
v² = u² + 2as
0² = u² + (2 × –20 × 295)
0 = u² + (–11800)
0 = u² – 11800
Collect like terms
0 + 11800 = u²
11800 = u²
Take the square root of both side
u = √11800
u = 108.6 ft/s
Therefore, the initial velocity of the car is 108.6 ft/s.
Finally, we shall determine the time taken for the car to stop as shown below:
Acceleration (a) = –20 ft/s² (since the car is coming to rest)
Final velocity (v) = 0 ft/s
Initial velocity (u) = 108.6 ft/s
Time taken (t) =?
v = u + at
0 = 108.6 + (–20 × t)
0 = 108.6 + (–20t)
0 = 108.6 – 20t
Collect like terms
0 – 108.6 = – 20t
– 108.6 = – 20t
Divide both side by –20
t = – 108.6 / –20
t = 5.43 s
Therefore, the time taken for the car to stop is 5.43 s.
