Answer:
Depends on how long the string is, how heavy the weight, and how high you let go of it.
But it will most likely hit you :)
Explanation:
First, find the velocity of the projectile needed to reach a height h when fired straight up.
Given:
Δy = h
v = 0
a = -g
Find: v₀
v² = v₀² + 2aΔy
(0)² = v₀² + 2(-g)(h)
v₀ = √(2gh)
Now find the height reached if the projectile is launched at a 45° angle.
Given:
v₀ = √(2gh) sin 45° = √(2gh) / √2 = √(gh)
v = 0
a = -g
Find: Δy
v² = v₀² + 2aΔy
(0)² = √(gh)² + 2(-g)Δy
2gΔy = gh
Δy = h/2
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Answer:
a) 4
b) 2
c) 8
Explanation:
In a cubic lattice, each atom of the vertex is shared among other 8 unit cells, so the atoms on the vertex contribute to 1/8 to a given unit cell.
a) Ina face-centered cubic we have 8 atoms on the vertex and one in each face, which is shared with another unit cell, so it contribute to 1/2
Therefore, the total atoms are:
8*(1/8) + 6*(1/2) = 4
b) In the body centered cubic structure, the centered atom is not shared with another cell, therefore it contribute to 1 to the given cell:
The number of atoms per unit cel is:
8*(1/8) + 1 = 2
c) The diamond lattice is similar to the face-centered cubic lattice but it contains two identical atoms per lattice point.
Therefore it must contain twice atoms than the face-centered cubic lattice:
that is, it has 8 atoms per unit cell
