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Anika [276]
3 years ago
10

how large can the kinetic energy of an electron be that is localized within a distance (change in) x = .1 nmapproximately the di

ameter of a hydrogen atom (ev)
Physics
1 answer:
elena-14-01-66 [18.8K]3 years ago
4 0

Answer:

The kinetic energy of an electron is 1.54\times10^{-15}\ J

Explanation:

Given that,

Distance = 0.1 nm

We need to calculate the momentum

Using uncertainty principle

\Delta x\Delta p\geq\dfrac{h}{4\pi}

\Delta p\geq\dfrac{h}{\Delta x\times 4\pi}

Where, \Delta p = change in momentum

\Delta x = change in position

Put the value into the formula

\Delta p=\dfrac{6.6\times10^{-34}}{4\pi\times10^{-10}}

\Delta p=5.3\times10^{-23}

We need to calculate the kinetic energy for an electron

K.E=\dfrac{p^2}{2m}

Where, P = momentum

m = mass of electron

Put the value into the formula

K.E=\dfrac{(5.3\times10^{-23})^2}{2\times9.1\times10^{-31}}

K.E=1.54\times10^{-15}\ J

Hence, The kinetic energy of an electron is 1.54\times10^{-15}\ J

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Since the CONDENSING TEMPERATURE for 417.4 psig discharge pressure is 120 degrees (120°) which means that the amount of subcooling that is there in the condenser will be calculated using this formula

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