determinar el valor de la velocidad que lleva un cuerpo cuya masa es 3kg y su energia cinetica es de 400Joule
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Answer:
The answer is 2,416 m/s. Let's jump in.
Explanation:
We do work with the amount of energy we can transfer to objects. According to energy theory:
W = ΔE
Also as we know W = F.x
We choose our reference point as a horizontal line at the block's rest point.<u> At the rest, block doesn't have kinetic energy</u> and <u>since it is on the reference point(as we decided) it also has no potential energy.</u>
Under the force block gains;
W = F.x →
In the second position block has both kinetic and potential energy. Following the law of conservation of energy;
W = ΔE = Kinetic energy + Potantial Energy
W = ΔE =
Here we can find h in the triangle i draw in the picture using sine theorem;
In a triangle
In our situation
→
Therefore
→
To solve this problem it is necessary to apply an energy balance equation in each of the states to assess what their respective relationship is.
By definition the energy balance is simply given by the change between the two states:
Our states are given by
In this way the energy balance for the states would be given by,
Therefore the states of energy would be
Lowest : 0.9eV
Middle :7.5eV
Highest: 8.4eV