The distance travelled is 10 m and the velocity gained at the end of this time is 2 m/s.
<h3>Velocity of the object at the end of the time</h3>
F = mv/t
where;
- m is mass of the object
- v is velocity of the object
- t is time
Ft = mv
v = Ft/m
v = (50 x 10)/250
v = 2 m/s
<h3>Distance traveled by the object</h3>
v² = u² + 2as
where;
u is initial velocity = 0
a is acceleration
a = F/m
a = 50 N/ 250 kg
a = 0.2 m/s²
v² = 0 + 2as
s = v²/2a
s = (2²)/(2 x 0.2)
s = 10 m
Thus, the distance travelled is 10 m and the velocity gained at the end of this time is 2 m/s.
Learn more about distance here: brainly.com/question/2854969
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Answer:
a) Tc = 750 [N] ;b) See the explanation below.
Explanation:
To solve this problem, we first need a graphical explanation of this, as well as knowing the corresponding questions. Therefore, a search was carried out in google, in the attached image we will find a graphical description of the problem.
b)
The solution of this type of problem corresponds to the use of Newton's third law, applying static which tells us that the sum of the forces in a system in equilibrium without movement must be equal to zero.
a)
In this way we can find by means of a sum of forces on the y axis equal to zero:
- 850 - 450 + 550 + Tc = 0
Tc = 750 [N]