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3 years ago

What are the domain, range, and midline of the function f(x)=1/2cos(1/4x)-1?

Mathematics

2 answers:

erma4kov [3.2K]3 years ago

8 0

Your function is: $f(x)=\frac{1}{2}\cos \Big( \frac{1}{4x}\Big) -1$

Domain: $(-\infty, +\infty)-\{ 0 \}$ or $R-\{ 0 \}$

Range: $[-\frac{3}{2}, -\frac{1}{2}]$

Midline: $y=-1$

prisoha [69]3 years ago

5 0

I’m not sure but next time a picture of the question might help!

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This is the new update of the question

anzhelika [568]

Answer:

Step-by-step explanation:

If x represents the slant height, the graph would be a straight line.

If x represents the radius, the graph would be a parabola.

Looking at the answers, we're looking for x to be the slant height, so we're looking for a straight line.

We are looking for g(x). Answers a and b are wrong.

In g(x) r is fixed to 5 (this is given). So the slant height in the smallest possible cone would still be at least 5.

So the domain is x > 5.

d is your answer.

8 0

3 years ago

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The price of an item has risen to $91 today. yesterday it was $65 l. find the percentage increase

Natali [406]

Answer:

40%

Step-by-step explanation:

First you take $19 - $65 to get $26

Then: 26 ×100= 2600÷ 65= 40%

8 0

3 years ago

Polygon CCC has an area of 404040 square units. K 2ennan drew a scaled version of Polygon CCC using a scale factor of \dfrac12 1

nikdorinn [45]

Answer:

Area of polygon D = 10 square units

Step-by-step explanation:

Given:

Polygon C has an area of 40 square units.

It is scaled with a scale factor of $\frac{1}2$ to form a new polygon D.

To find:

The area of polygon D = ?

Solution:

When any polygon is scaled to half, then all the sides of new polygon are half of the original polygon.

And the area becomes one-fourth of the original polygon.

Let us consider this by taking examples:

First of all, let us consider a right angled triangle with sides 6, 8 and 10 units.

Area of a right angled triangle is given by:

$A = \dfrac{1}{2} \times Base \times Height\\\Rightarrow A = \dfrac{1}{2} \times 6 \times 8 = 24\ sq\ units$

If scaled with a factor $\frac{1}{2}$ , the sides will be 3, 4 and 5.

New area, A':

$A' =\dfrac{1}{2} \times 3 \times 4 = 6\ sq\ units = \dfrac{1}4\times A$

i.e. Area becomes one fourth.

Let us consider a rectangle now.

Sides be 8 and 10 units.

Area of a rectangle, A = $Length \times Width$ = 8 $\times$ 10 = 80 sq units.

Now after scaling, the sides will be 4 and 5 units.

New Area, A' = 4 $\times$ 5 =20 sq units

So, $\bold{A' = \frac{1}4 \times A}$

Now, we can apply the same in the given question.

$\therefore$ Area of polygon D = $\bold{\frac{1}{4}}$ $\times$ Area of polygon C

Area of polygon D = $\bold{\frac{1}{4}}$ $\times$ 40 = 10 sq units

4 0

3 years ago

Why are 5:7 and 10:14 equivalent?

MAVERICK [17]

Answer:

Because 5+5=10 and 7+7=14

4 0

2 years ago

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What would be the steps to solving this problem? <img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B3%7D" id="TexFormula

lidiya [134]

Isolate the variable by dividing each side by factors that don’t contain the variable.

X = -2

Hope this helps!
Have a great day!

3 0

2 years ago

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What are the domain, range, and midline of the function f(x)=1/2cos(1/4x)-1?​

What are the domain, range, and midline of the function f(x)=1/2cos(1/4x)-1?