What are the domain, range, and midline of the function f(x)=1/2cos(1/4x)-1?
2 answers:
You might be interested in
The standard form of an equation is
In the question, we have the following formula
To get the formula in standard form, we first have to subtract 2y from both sides (since we need to get 2y on the left side)
Finally we subtract 1 from both sides (since we need the number on the right side)
Hence, 4. is the correct answer.
In the question, we have the following formula
To get the formula in standard form, we first have to subtract 2y from both sides (since we need to get 2y on the left side)
Finally we subtract 1 from both sides (since we need the number on the right side)
Hence, 4. is the correct answer.
Answer:
a. Vertex = (2.5,-12.25)
b. y-intercept = (0,-6)
c. x-intercept = (6,0) ; (-1,0)
Step-by-step explanation:
a.
Your equation is written as:
The easiest way to find the vertex is writing the equation this way:
Being the vertex (h,k)
So first complete the square
Vertex : (2.5,-12.25)
b.
To find the y-intercept you need to replace the equation when x = 0 and get y
c.
To find the x-intercept you need to replace the equation when y = 0 and get x