Question

please help i really need to know how to solve 11 and 12. were solving each equation for y in terms of x

Answer 1

Step-by-step explanation:

$11) \: \\ 3x + 2y - 6 = 0 \\ \therefore \: 3x + 2y = 6 \\ \therefore \: 2y = 6 - 3x \\ \therefore \: y = \frac{6 - 3x}{2} \\ \therefore \: y = \frac{6}{2} - \frac{3}{2} x \\ \\ \huge\therefore \: y = 3- \frac{3x}{2} \\ \\ 12) \\ x - 4y + 2 = 0 \\ x + 2 = 4y \\ \therefore \:4y = x + 2 \\ \therefore \:y = \frac{x}{4} + \frac{2}{4} \\ \huge \therefore \:y = \frac{x}{4} + \frac{1}{2}$