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Pavel [41]
3 years ago
14

There are 8 action, 3 comedy, and 5 drama DVDs on a shelf. Suppose three DVDs are selected at random from the shelf. Find each p

robability.
P(2 action, then a comedy), without replacement.
Mathematics
1 answer:
nordsb [41]3 years ago
4 0
8 action, 3 comedy, 5 drama....total = 16 dvd's

P(2 action, then a comedy)...without replacement

8/16 * 7/15 * 3/14 = (8 * 7 * 3) / (16 * 15 * 14) = 168/3360 = 1/20
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Connor went to new york for vacation. he spent 3 nights at a hotel and rented a car for 4 days. jillian stayed at the same hotel
Vikentia [17]

<em>Answer : C: $125.</em>

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8 0
3 years ago
One-half of a number,<br> increased by 69 is 74.<br> What is the number?
Klio2033 [76]

Answer:

10

Step-by-step explanation:

let the number be n then half the number is \frac{1}{2} n , so

\frac{1}{2} n + 69 = 74 ( subtract 69 from both sides )

\frac{1}{2} n = 5 ( multiply both sides by 2 to clear the fraction )

n = 10

Thus the number is 10

6 0
2 years ago
Read 2 more answers
Solve the following equation: lim x-&gt;0 sin3x/5x^3-4x.
goblinko [34]
Usual limit of sin is sinX/X--->1, when X--->0

sin3x/5x^3-4x=0/0?, sin3x/3x--->1 when x --->0, so sin3x/5x^3-4x=                    [3x. sin3x / 3x] /(5x^3-4x)=(sin3x / 3x) . (3x/5x^3-4x)
   =(sin3x / 3x) . (3/5x^2- 4)
finally lim  sin3x/5x^3-4x=lim (sin3x / 3x) .(3/5x^2- 4)=1x(3/-4)= - 3/4
                 x----->0            x---->0
3 0
3 years ago
Work for determining system for log base radical 2 of e​
igomit [66]

Answer:

4 ok bye

Thank you

Babye❤️

7 0
3 years ago
Match each expression in the left column with the correct product in the right column.
lesya692 [45]

Answer:

-6

-6i

6i

6

Step-by-step explanation:

1) √4 . √-3 . √-3

$ \sqrt{4} = 2 $

$ \sqrt{-3} . \sqrt{-3} = (\sqrt{-3})^2 $

$ \sqrt{4} . (\sqrt{-3})^2 = 2 \times -3 = $ -6

2) √-4 . √-3 . √-3

$ \sqrt{-4} = 2i $ .

Therefore, $ \sqrt{-4} . \sqrt{-3} . \sqrt{-3} = 2. \sqrt{-1}  \times -3 = 2i \times (-3) =  $ - 6i

3) √4 . √3 . √-3

$ \sqrt{4} = 2 $

$ \sqrt{3} . \sqrt{-3} = (\sqrt{3})^2 . \sqrt{-1} $

$ \implies 2 \times 3i = $ 6i

4) √4 . √3 . √3

$ \sqrt{4} = 2 $

$ \sqrt{3} . \sqrt{3} = (\sqrt{3})^2  = 3 $

Therefore, √4 . √3 . √3 = 2 . 3 = 6

5 0
3 years ago
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