3 years ago

21 square root of $42.84

Mathematics

1 answer:

jekas [21]3 years ago

5 0

21√$42.84 ≈ 21√42.84=137.449773

Hope this helps~!

You might be interested in

(35 + 5)[16 + (12 divide 4)]

nadezda [96]

Answer:

Step-by-step explanation:

8 0

3 years ago

The real numbers $x$ and $y$ are such that \begin{align*} x + y &= 4, \\ x^2 + y^2 &= 22, \\ x^4 &= y^4 - 176 \sqrt{

tamaranim1 [39]

You get everything you need from factoring the last expression:

$x^4-y^4=-176\sqrt7$

The left side is a difference of squares, and we get another difference of squares upon factoring. We end up with

$x^4-y^4=(x^2-y^2)(x^2+y^2)=(x-y)(x+y)(x^2+y^2)$

Plug in everything you know and solve for $x-y$ :

$-176\sqrt7=(x-y)\cdot4\cdot22\implies x-y=\boxed{-2\sqrt7}$

4 0

3 years ago

Read 2 more answers

67.5 into a fraction

andrey2020 [161]

Answer:

67 1/2

Step-by-step explanation:

67 5/10

67 1/2

3 0

3 years ago

Read 2 more answers

PLEASE HELP I WILL GIVE BRAINLEST!!!

Furkat [3]

Answer:

=16+9=25

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Find the square: (5x - 4y)2 <br><br> (and please put the process of solving the equation)

satela [25.4K]

$(5x-4y)^2$
$(5x-4y)(5x-4y)$

Multiply each term in one bracket in turn by the terms in the other bracket

$(5x)(5x) = 25x^2$
$(5x)(-4y)=-20xy$
$(-4y)(5x)=-20xy$
$(-4y)(-4y)=16y^2$

Put them together we have
$25x^2-20xy-20xy-16y^2$
$25x^2-40xy-16y^2$

7 0

2 years ago