Answer:
Step-by-step explanation:
Ok, let's do this step by step....
Let's first simplify the x's:
Then we breakdown the 54 as 2 * 27 then simplify with the 10 above.
Now, we can rewrite this as the following and solve the bottom part:
The solution is
Answer: 6.5 hours
Step-by-step explanation:
You have to find out how long it’ll take, so you divide the total amount by the speed, so 455/70=6.5
N=2
The smallest value of f(x) on [0, π/2] is 2, which occurs at x = 0. The smallest value of f(x) on [π/2, π] is also 0, which occurs at x = π. So the lower sum is (π/2)(2 + 2) = 2π
The largest value of f(x) on [0, π/2] is 3, which occurs at x = π/2. This is also true for the interval [π/2, π]. So the upper sum is (π/2)(3 + 3) = 3π
n = 4:
f '(x) = cos(x), which is positive for [0, π/2) and negative for (π/2, π]. This tells us that f is an increasing function on [0, π/2) and a decreasing function on (π/2, π]. So for the lower sum you will always evaluate f at the left endpoint of the subinterval if that subinterval lies in [0, π/2], and at the right endpoint of the subinterval if it lies in [π/2, π]
Thus, the lower sum for n = 4 is
(π/4)(f(0) + f(π/4) + f(3π/4) + f(π))
and the upper sum is
(π/4)(f(π/4) + f(π/2) + f(π/2) + f(3π/4)).
the lower sum for n=8 is
(π/8)(f(0)+f(π/8)+f(π/4)+f(3π/8)+f(5π/8...
and the upper sum is
(π/8)(f(π/8)+f(π/4)+f(3π/8)+f(π/2)+f(π/...
Answer: 2x + 0.5 unit
Step-by-step explanation:
A square has 4 equal sides. Therefore, its perimeter is calculated by adding the four sides.
Since the perimeter of a square is 8x +2 units, to get the length of one side, we divide the perimeter by 4. This will be:
= (8x + 2)/4
= 2x + 0.5
Therefore, the length of one side is 2x + 0.5 unit
The amount that the man have in his bank at the second year is $100,352.
Using this formula
A=P(1+R÷100)^n
Where:
A=Amount
P=Principal=$80,000
R=Rate=12%
n=Number of years=2 years
Let plug in the formula
A=$80,000(1+12÷100)^2
A=$80,000(1+0.12)^2
A=$80,000(1.12)^2
A=$80,000(1.2544)
A=$100,352
Inconclusion the amount that the man have in his bank at the second year is $100,352.
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