All categories

3 years ago

4^0.5= Choices -2 1/2 2

Mathematics

2 answers:

Viefleur [7K]3 years ago

5 0

The answer is 2

Plug in on calculator 4^0.5 equals 2

IgorC [24]3 years ago

4 0

Answer:

$2$

Step-by-step explanation:

$4=2^2$

$\left(2^2\right)^{\frac{1}{2}}$

$\left(2^2\right)^{\frac{1}{2}}=2^{2\cdot \frac{1}{2}}$

$2^{2\cdot \frac{1}{2}}=2$

$2$

You might be interested in

What are the ratios for sin A and cos A? The triangle is not drawn to scale.

dalvyx [7]

Answer:

$SinA = \frac{84}{85}$ and $CosA=\frac{13}{85}$

Step-by-step explanation:

The ratios of sine and cos are defined as follows:

$Sin A = \frac{Opposite}{Hypotenuse}$ , and

$CosA = \frac{Adjacent}{Hypotenuse}$

The hypotenuse is always the side opposite of the 90 degree angle (for the given triangle, the hypotenuse is 85)

Since we are looking at the angle A, the opposite side with respect to A would be the side length of 84. That leaves the side 13 as the adjacent side.

Thus, we can now write:

$Sin A = \frac{Opposite}{Hypotenuse}\\SinA = \frac{84}{85}$

$CosA = \frac{Adjacent}{Hypotenuse}\\CosA=\frac{13}{85}$

The correct answer is the first answer choice.

7 0

3 years ago

If D is the midpoint of CE, CD= 9x-7, and DE= 3x+17, find CE

tatuchka [14]

Hello!

Since D is the midpoint and the two equations are and both sides of point D the equations equal each other

9x - 7 = 3x + 17

Now you solve it algebraically

Add 7 to both sides

9x = 3x + 24

Subtract 3x from both sides

6x = 24

Divide both sides by 6

x = 4

Now we put this into both equations and add them

9(4) - 7 = 29
3(4) + 17 = 29

29 + 29 = 58

The answer is 58 units

Hope this helps!

3 0

2 years ago

Explain the process in detail on how to solve the following question for

OleMash [197]

Sks skewhwjebslsgeowbz

3 0

3 years ago

If one root is the square of the other in the equation 8+mx+27x²=0,find the value of m

aleksklad [387]

Answer:

The value of $m$ is -30.

Step-by-step explanation:

Let $27\cdot x^{2}+m\cdot x +8 = 0$ , we notice that expression is a second order polynomials. We can rearrange the polynomial and use factorization to calculate all roots: