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Lesechka [4]
3 years ago
15

Turn this into an equation. what percent of 1800 is 20.

Mathematics
1 answer:
Talja [164]3 years ago
8 0
1800x = 20 is the equation
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Actorize Completely PQ+ PR - RQ -Q²​
sp2606 [1]

Answer:

(Q + R)(P - Q)

Step-by-step explanation:

PQ + PR - RQ - Q²​ = (Q + R)(P - Q)

8 0
2 years ago
Jan wants to paint her bedroom that measures 15 feet wide, 20 feet long, and 8 feet high. One gallon of the paint she selects co
trasher [3.6K]

Answer:

Step-by-step explanation:

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3 years ago
How many numbers lie between the square of 56 and 57
NARA [144]

Answer:

Given, two numbers 56 and 57 we need to find out the numbers lie between the squares of the given numbers.

Now, we have numbers lying between the square of n and (n + 1) is 2n

⇒ Numbers between squares of 56 and (56 + 1) = 2 × 56 = 112

Hence, 112 numbers lies between the square of the given numbers.

7 0
2 years ago
Read 2 more answers
The length of the garden is 11 yards.The width of the garden is 8 yards. Select all of the expressions that chole could use to f
Sati [7]

Answer:

The length of the fence is 38 yards

These are the expressions

1. Perimeter = 2l+ 2w

2. Perimeter = 2(l+w)

Step-by-step explanation:

This problem bothers on the mensuration of flat shapes, a rectangle.

The length of the fence is the perimeter of the garden which is the expression that Chole could use

1. Perimeter = 2l+ 2w

2. Perimeter = 2(l+w)

Given data

Length = 11 yards

Width = 8 yards

Perimeter = 2(11)+ 2(8)

Perimeter = 22+16

Perimeter = 38 yards

3 0
2 years ago
Denise is planning to put a deck in her back yard. The deck will be a 10-by-7-foot rectangle with a semicircle of diameter 4 fee
vladimir2022 [97]

Answer:

approx. = 85.28 {ft}^{2}

Step-by-step explanation:

You can think of this as adding the area of the rectangular portion of the deck (length x width) and the semicircular portion (πr^2)/2.

(l×w)+(πr^2)/2

(10×7)+((π2^2)/2

79+2π

approx. = 85.28 {ft}^{2}

3 0
3 years ago
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