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san4es73 [151]
3 years ago
9

Find the greatest 3 digit number which when divided by 75,45 and 60 leaves no remainder and the remainder 4 in each case

Mathematics
1 answer:
pishuonlain [190]3 years ago
7 0
LCM of 75,45 and 60 is 900.
The divisor of 75,45 and 60 must be a multiple of their LCM.
75×900=67500 )⤵
45×900=40500 )↪ not a 3 digits no.
60×900=54000 )⤴
Since they are not 3 digits no..the greatest 3 digits no exactly divisible by 75,45,60 must be the LCM itself i.e. 900 >>Ans

Now,the next question is very simple.As the 900
greatest divisor of all given no., add 4 to get remainder 4 when divided by 75,60 and 45.
So, ans=904
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A game is said to be fair if the expected value (after considering the cost) is 0. This would mean that in the long run, both th
algol13

Answer:

The expected value is 0

Game is fair

Step-by-step explanation:

Probability = required outcome / Total possible outcomes

Number of red cards = 26

Numbw rof black cards = 26

Total number of cards = 52

If a red card is chosen, amount paid is doubled

If a black card is chosen, no winning or amount is collected.

Net money won or lost on choosing a red card = ($2 - $1) = $1

Net amount won on choosing a black card = $0 - $1 = - $1

P(red) = 26 /52 = 1/2

P(blue) = 26 /52 = 1/2

Expected value (E):

E = x*p(x)

E(X) = (1/2 * 1) + (1/2 * - 1)

E(X) = 1/2 - 1/2 = 0

Hence, since the expected value is 0 ; then the game is fair

5 0
3 years ago
What is the integer that is closer to the square root of 35
Murrr4er [49]
Here’s your answer get the app socratic

8 0
3 years ago
A line with a slope of 3 passes through the point (2, 6). What is its equation
Vlada [557]

Answer:

I found: y=−3x+12

Explanation:

You can use the relationship:

y−y0=m(x−x0)

Where m is the slope and x0,y0 the coordinates of your point.

So with your data:

y−6=−3(x−2)

y=−3x+6+6

y=−3x+12

or:

3x+y=12

4 0
3 years ago
Find the area enclosed by the curve<br> x = t2 − 2t, y = t and the y-axis.
MA_775_DIABLO [31]
The curve hits the y-axis whenever x=0:

x=t^2-2t=0\implies t(t-2)=0\implies t=0,t=2

The area enclosed by the region is the sum of distances of every point on the curve where t\in[0,2] to the origin. This is given by the integral

\displaystyle\int_0^2\sqrt{x(t)^2+y(t)^2}\,\mathrm dt
\displaystyle\int_0^2\sqrt{(t^2-2t)^2+t^2}\,\mathrm dt
\displaystyle\int_0^2\sqrt{t^2(t-2)^2}\,\mathrm dt
\displaystyle\int_0^2|t||t-2|\,\mathrm dt

Since t\in[0,2], you have |t|=t and |t-2|=-(t-2)=2-t, giving you

\displaystyle\int_0^2(2t-t^2)\,\mathrm dt=t^2-\dfrac{t^3}3\bigg|_{t=0}^{t=2}=4-\dfrac83=\dfrac43
7 0
3 years ago
Simplify <br>−2(j^2− k) − 6(j^2 + 3k )
Fantom [35]

Answer:-8j^2-16k

Step-by-step explanation:

First step:-2j^2-(-2)k=-2j^2+2k

Second step:

-6(j^2+3k) use the formula a(b+c)=ab + ac

a=-6 b=j^2 c=3k

-6j^2+(-6).3k

-6j^2-6.3k=-6j^2-18k because we multiplied 6x3=18

So we gather the whole equation And simplify

-2j^2+2k-6j^2-18k

-2j^2-6j^2 +2k-18k(add like terms)6+2=8

-8j^2+2k-18K (subtract Like terms 18-2=16)

And the answer will give -8j^2-16k

3 0
3 years ago
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