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san4es73 [151]
3 years ago
9

Find the greatest 3 digit number which when divided by 75,45 and 60 leaves no remainder and the remainder 4 in each case

Mathematics
1 answer:
pishuonlain [190]3 years ago
7 0
LCM of 75,45 and 60 is 900.
The divisor of 75,45 and 60 must be a multiple of their LCM.
75×900=67500 )⤵
45×900=40500 )↪ not a 3 digits no.
60×900=54000 )⤴
Since they are not 3 digits no..the greatest 3 digits no exactly divisible by 75,45,60 must be the LCM itself i.e. 900 >>Ans

Now,the next question is very simple.As the 900
greatest divisor of all given no., add 4 to get remainder 4 when divided by 75,60 and 45.
So, ans=904
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Solve the equation:<br> 5|2x-7|=20
MA_775_DIABLO [31]

Answer:

x = \frac{11}{2}, \frac{3}{2}

Step-by-step explanation:

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6 0
3 years ago
Read 2 more answers
1/2 + 5/3 - 1<br>------------------<br> 3/4
Sav [38]
Hey there :)

\frac{ \frac{1}{2}+ \frac{5}{3} -1 }{ \frac{3}{4} }
      ↓ Is the same as
\frac{1}{2} + \frac{5}{3} -1 ÷ \frac{3}{4}

Since it is a division by fraction, we can multiply by what is called the reciprocal
( The attached picture might help you )
( \frac{1}{2} + \frac{5}{3} - 1 ) × \frac{4}{3} 
     ↓ For this part, we need the common denominator, which is 6
\frac{1(3)}{2(3)}+ \frac{5(2)}{32)}  \frac{1(6)}{1(6)} × \frac{4}{3}

\frac{3}{6}+ \frac{10}{6}  - \frac{6}{6} × \frac{4}{3}
\frac{7}{6} × \frac{4}{3}
\frac{14}{9} =  1\frac{5}{9}
  ↑
Your final answer
 

7 0
3 years ago
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