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Paul [167]
3 years ago
5

Help me solve this equation and explain how you got the answer! I’ll give you brainliest

Mathematics
1 answer:
Alborosie3 years ago
3 0
The answer to ur question is a
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I am Lyosha [343]

Answer: the distance is 8

Step-by-step explanation:

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3 years ago
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Rashid [163]
Table a is 3 b is 2 and c is 1
7 0
3 years ago
Simplify each expression
Rzqust [24]

Answer:

See below

Step-by-step explanation:

1.

-6(a + 8)

Distribute the -6.

-6a - 48

2.

4(1 + 9x)

Distribute the 4.

4 + 36x or 36x + 4

3.

6(-5n + 7)

Distribute the 6.

-30n + 42

4.

(9m + 10) * 2

Rewrite.

2(9m + 10)

Distribute the 2.

18m + 20

5.

(-4 - 3n) * -8

Rewrite.

-8(-4 - 3n)

Distribute the -8.

32 + 24n or 24n + 32

6.

8(-b - 4)

Distribute the 8.

-8b - 32

7.

(1 - 7n) * 5

Rewrite.

5(1 - 7n)

Distribute the 5.

5 - 35n or -35n + 5

8.

-6(x + 4)

Distribute the -6.

-6x - 24

9.

5(3m - 6)

Distribute the 5.

15m - 30

10.

(-6p + 7) * -4

Rewrite.

-4(-6p + 7)

Distribute the -4.

24p - 28

11.

5(b - 1)

Distribute the 5.

5b - 5

12.

(x + 9) * 5

Rewrite.

5(x + 9)

Distribute the 5.

5x + 45

5 0
3 years ago
Please help i need
Anon25 [30]

The measure of centre includes mean median and mode and the measure of variability includes range, interquartile range and mean absolute deviation.

<h3>what is measure centre and measure of variation? </h3>

A measure of central tendency (measure of centre) is a value that attempts to describe a set of data by identifying the central position of the data set.

The measure of central tendency includes the mean, median and mode.

The measure of variation describes the amount of variability or spread in a set of data.

The common  measures of variability are the range, the interquartile range (IQR), variance, and standard deviation.

Therefore, the measure of centre includes mean median and mode and the measure of variability includes range, interquartile range and mean absolute deviation.

learn more on measure of centre and variation here: brainly.com/question/23769503

#SPJ1

7 0
2 years ago
An athlete knows that when she jogs along her neighborhood​ greenway, she can complete the route in 10 minutes. It takes 20 minu
IgorLugansk [536]

Answer:

10 miles per hour.

Step-by-step explanation:

Let x represent athlete's walking speed.

We have been given that her jogging rate is 5 mph faster than her walking​ rate, so athlete's jogging speed would be x+5 miles per hour.

\text{Distance}=\text{Rate}\cdot \text{Time}

10 minutes = 1/6 hour.

20 minutes = 1/3 hour

While walking, we will get D_{\text{walking}}=x\frac{\text{miles}}{\text{hour}}\cdot \frac{1}{3}\text{hour}

D_{\text{walking}}=\frac{x}{3}

While jogging, we will get D_{\text{jogging}}=(x+5)\frac{\text{miles}}{\text{hour}}\cdot \frac{1}{6}\text{hour}

D_{\text{jogging}}= \frac{(x+5)}{6}

Since athlete is covering same distance while walking and jogging, so we can equate both expressions as:

\frac{x}{3}=\frac{x+5}{6}

Cross multiply:

6x=3x+15

6x-3x=15

3x=15

\frac{3x}{3}=\frac{15}{3}\\\\x=5

Therefore, athlete's walking speed is 5 miles per hour.

Jogging speed: x+5\Rightarrow 5+5=10

Therefore, athlete's jogging speed is 10 miles per hour.

3 0
3 years ago
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