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nadya68 [22]
3 years ago
15

When would a measurement be both accurate and precise?

Chemistry
1 answer:
alina1380 [7]3 years ago
6 0

Answer:C) the measurement is close to the accepted value and can be reproduced.

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Romashka [77]
The answer is the el second one since it is a physical change
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Atomic emission spectra are unique to each element. true false
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True, bc each element emits lights that have an unique wavelength and frequency
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Read 2 more answers
A laboratory analysis of a 100 g sample finds it is composed of 1.8 g hydrogen, 56.1 g sulfur, and 42.1 g oxygen. What is its em
Neporo4naja [7]

Answer: The empirical formula is H_2S_2O_3

Explanation:

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mas of H = 1.8 g

Mass of S = 56.1 g

Mass of O = 42.1 g

Step 1 : convert given masses into moles.

Moles of H =\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{1.8g}{1g/mole}=1.8moles

Mass of S =\frac{\text{ given mass of S}}{\text{ molar mass of S}}= \frac{56.1g}{32g/mole}=1.8moles

Moles of O=\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{42.1g}{16g/mole}=2.6moles

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For H = \frac{1.8}{1.8}=1

For S = \frac{1.8}{1.8}=1

For O =\frac{2.6}{1.8}=1.5

Converting to whole number ratios

The ratio of H: S: O= 2: 2: 3

Hence the empirical formula is H_2S_2O_3

7 0
3 years ago
What class of elements includes all of the elements that are gases at room temperature? nonmetals metals metalloids?
Novay_Z [31]
Metals have high density. They are always solids at room temperature.
Metalloids have intermediate density. They are generally solids at room temperature.
Non-metals have low density. They can be solids, liquids or gases at room temperature.

Based on this, the <span>class of elements that includes all of the elements that are gases at room temperature is the non-metals</span>
6 0
3 years ago
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If you only have 36.5 grams of Potassium Carbonate (K2CO3 molar mass = 138.2 g/mole). How many liters of a 0.52 M solution can y
kirza4 [7]

Answer:

0.508 L of solution.

Explanation:

Always a safe bet to convert to moles:

n= {m \over MM}\\

Where n is moles, m is mass, and MM is molar mass.

Now remember the equation for concentration (molarity):

C={n \over V}

Where C is the concentration, n is moles, and V is volume.

To make this easy, combine the two equations (note n appears in both, so you can do a substitution) and solve for V as the question asks:

C={m \over MM \times V}\\0.52={36.5 \over 138.2 \times V}\\V={36.5 \over 138.2 \times 0.52}\\V=0.508

Therefore we can make 0.508 L of solution.

8 0
3 years ago
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