Question

If you only have 36.5 grams of Potassium Carbonate (K2CO3 molar mass = 138.2 g/mole). How many liters of a 0.52 M solution can you make?

Answer 1

Answer:

0.508 L of solution.

Explanation:

Always a safe bet to convert to moles:

$n= {m \over MM}$

Where n is moles, m is mass, and MM is molar mass.

Now remember the equation for concentration (molarity):

$C={n \over V}$

Where C is the concentration, n is moles, and V is volume.

To make this easy, combine the two equations (note n appears in both, so you can do a substitution) and solve for V as the question asks:

$C={m \over MM \times V}\\0.52={36.5 \over 138.2 \times V}\\V={36.5 \over 138.2 \times 0.52}\\V=0.508$

Therefore we can make 0.508 L of solution.