Graph the line with slope -1 passing through the point (-2, -2).

1 answer:

4 0

$\bf slope = {{ m}}= \cfrac{rise}{run} \implies -1\implies \cfrac{-1}{1}
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\textit{that means, from point} ~\boxed{(-2,-2)}\\\\
\textit{you go -1 over the y-axis and 1 over the x-axis}
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(\stackrel{run}{-2}~,~\stackrel{rise}{-2})\\\\\\ (\stackrel{1}{-2}~,~\stackrel{-1}{-2})\implies (-2+1~,~-2-1)\implies \boxed{(-1,-3)}$

so.... there, using the slope's rise/run values, you can get the subsequent point, and to graph a LINEar equation, since it's just a LINE, all you need is two points, graph those two, run a line through them, that's the graph of the line.

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