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ANTONII [103]
3 years ago
9

Quiz consists of 60 true or false questions. If the student guesses on each​ question, what is the standard deviation of the num

ber of correct​ answers? Round to the nearest thousandth.
2 0r 3.873 or 0 or 5.477
Mathematics
1 answer:
anyanavicka [17]3 years ago
6 0

Answer:

5.477 ok my friend oooooo

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What would be a equation for (5,2) and (0,7)?
Genrish500 [490]

\bf (\stackrel{x_1}{5}~,~\stackrel{y_1}{2})\qquad (\stackrel{x_2}{0}~,~\stackrel{y_2}{7}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{7}-\stackrel{y1}{2}}}{\underset{run} {\underset{x_2}{0}-\underset{x_1}{5}}}\implies \cfrac{5}{-5}\implies -1 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{2}=\stackrel{m}{-1}(x-\stackrel{x_1}{5}) \\\\\\ y-2=-x+5\implies y = -x+7

6 0
3 years ago
THIS IS WORTH 44 POINTS!!
alukav5142 [94]
Hello there! 


Your answer would be 

CAT (top line) = DBU (bottom line)


CAT (bottom line) = BZS (top line)


Hope I helped!

Let me know if you need anything else!

~ Zoe
7 0
3 years ago
Read 2 more answers
O A PQR is reflected over the x-axis. What are the<br> coordinates of O'?
topjm [15]

Answer:

(8,-2)

Step-by-step explanation:

When reflecting something across the X axis the y axis coordinate is the one that will change to put the position further up or down.  In this case we are moving it down to the same amount below the axis that it is now above it.  That means that since it is currently 2 above the X axis it would then be 2 below the X axis making it at -2 so the coordinates would be (8,-2)

I hope this helps and please don't hesitate to ask if there is anything still unclear!

7 0
3 years ago
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Find the value of tan theta if sin theta = 12/13 and theta is in quadrant 2
8090 [49]

Answer:

tanΘ = - \frac{12}{5}

Step-by-step explanation:

Using the trigonometric identities

• sin²x + cos²x = 1, hence

cosx = ± √(1 - sin²x )

• tanx = \frac{sinx}{cosx}

given sinΘ = \frac{12}{13}, then

cosΘ = ±  \sqrt{1-(12/13)^2}

Since Θ is in the second quadrant where cosΘ < 0, then

cosΘ = - \sqrt{1-\frac{144}{169} }

         = - \sqrt{\frac{25}{169} } = - \frac{5}{13}

tanΘ = \frac{\frac{12}{13} }{\frac{-5}{13} }

        = \frac{12}{13} × - \frac{13}{5} = - \frac{12}{5}



5 0
3 years ago
I.5y=2x-5<br> II.5y=4+3x<br> III.5y-3x=-1
Ratling [72]

Answer:

Step-by-step explanation:

the vale of x differs in each situation are we talking AB value

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