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4 years ago

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A man weighing 680N and a woman weighing 500N have the same momentum. What is the ratio of the man's kinetic energy Km to that o

f the woman Kw?
A cardinal (Richmondena cardinalis) of mass 3.60

1 answer:

svet-max [94.6K]4 years ago

3 0

Answer:

$\dfrac{K_m}{K_w}=0.734$

Explanation:

given,

weight of the man = 680 N

weight of the woman = 500 N

mass of man = $\dfrac{680}{9.8}$

M_m = 69.4 Kg

mass of woman

= $\dfrac{500}{9.8}$

M_w = 51 Kg

ratio of man's kinetic energy Km to that of the woman Kw

$\dfrac{K_m}{K_w}=\dfrac{\dfrac{P_m^2}{2M_m}}{\dfrac{P_w^2}{2M_w}}$

momentum is same

$\dfrac{K_m}{K_w}=\dfrac{2M_w}{2M_m}$

$\dfrac{K_m}{K_w}=\dfrac{M_w}{M_m}$

$\dfrac{K_m}{K_w}=\dfrac{51}{69.4}$

$\dfrac{K_m}{K_w}=0.734$

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