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timama [110]
3 years ago
9

Jeannette's starting salary is $25,000 a year. she will get a 4% raise annually. how much money will she have made after 7 years

?
Mathematics
2 answers:
alexandr402 [8]3 years ago
7 0

It is given in the question that

Jeannette's starting salary is $25,000 a year. she will get a 4% raise annually.

And we have to find the amount of money she have made after 7 years .

Here we use the following formula

A = P(1+r)^t

P= 25000, r =0.04, t=7 years

Substituting these values, we will get

A = 25000(1+0.04)^7 = 25000(1.04)^7

A = 32898.29

Dmitrij [34]3 years ago
5 0
Jeannete would make 32,000 that year.

Hope this helped:D

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Exclude leap years from the following calculations. ​(a) Compute the probability that a randomly selected person does not have a
Scrat [10]

Answer:

a) 99.73% probability that a randomly selected person does not have a birthday on March 14.

b) 96.71% probability that a randomly selected person does not have a birthday on the 2 nd day of a month.

c) 98.08% probability that a randomly selected person does not have a birthday on the 31 st day of a month.

d) 92.33% probability that a randomly selected person was not born in February.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

A non-leap year has 365 days.

​(a) Compute the probability that a randomly selected person does not have a birthday on March 14.

There are 365-1 = 364 days that are not March 14. So

364/365 = 0.9973

99.73% probability that a randomly selected person does not have a birthday on March 14.

​(b) Compute the probability that a randomly selected person does not have a birthday on the 2 nd day of a month.

There are 12 months, so there are 12 2nds of a month.

So

(365-12)/365 = 0.9671

96.71% probability that a randomly selected person does not have a birthday on the 2 nd day of a month.

​(c) Compute the probability that a randomly selected person does not have a birthday on the 31 st day of a month.

The following months have 31 days: January, March, May, July, August, October, December.

So there are 7 31st days of a month during a year.

Then

(365-7)/365 = 0.9808

98.08% probability that a randomly selected person does not have a birthday on the 31 st day of a month.

(d) Compute the probability that a randomly selected person was not born in February.

During a non-leap year, February has 28 days. So

(365-28)/365 = 0.9233

92.33% probability that a randomly selected person was not born in February.

6 0
3 years ago
I need help please lol
xz_007 [3.2K]

Answer:

48.75

Step-by-step explanation:

3 0
3 years ago
Please help me out with solving these problems.​
timama [110]

Answer:

2l^2 + 2m^2 + 2n^2 + 2nl + 2lm + 2mn

Second one's answer ^

<em><u>Not sure about that first one..</u></em>

7 0
4 years ago
Distance (km)
Stolb23 [73]

Answer:

good and right and keep trying your best

6 0
2 years ago
how many different lock combinations can be made using the digits 8, 2, 8 and 8 if the 2 is only used once in each combination?​
alexandr402 [8]

2,8,8,8

8,2,8,8

8,8,2,8

8,8,8,2

4 combinations.

Hope this helps!

5 0
3 years ago
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