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Lena [83]
2 years ago
9

A broken clock loses four minutes every hour . If the broken clock and a normal clock are both set at noon what time will the no

rmal clock say when the broken clock reads 2:20pm
Mathematics
1 answer:
klio [65]2 years ago
5 0

Answer:

Time in normal clock = 2:30 PM

Step-by-step explanation:

Given:

Clock losses 4 min per hour

Total time = 2:20 Pm

Find:

Time in normal clock

Computation:

Total time = 2:20 = 2.333 hour

Total time losses = 2.333 x 4 min = 9.32 minutes (Approx)

Time in normal clock = 2:20 + 9.32 minutes (Approx)

Time in normal clock = 2:29.32 0r 2:30 PM

You might be interested in
Solve for x.<br><br> -5x = -10
andreev551 [17]

Answer:

x=2

Step-by-step explanation:

divide -5 to both sides to isolate the x. two negatives make a positive therefore x=2.

i hope this helps :)

6 0
2 years ago
Read 2 more answers
]7. A zucchini plant in Darnell’s garden was 13 centimeters tall when it was first planted. Since then, it has grown approximate
Pani-rosa [81]

Let d be the number of days and h be the height

h = 13 + 0.6d


Answer: (a) h = 13 + 0.6d


Given height = 0.208m, find d:


0.208m = 20.8 cm


20.8 = 13 + 0.6d

0.6d = 20.8 - 13 = 7.8

d = 7.8 ÷ 0.6 = 13


Answer: (b) 13 days






5 0
3 years ago
The sum of two numbers is 56. Their product is 108. Find the larger number?
lakkis [162]

Answer:

Step-by-step explanation:

The two numbers are 54 and 2

Their sum = 54 + 2 = 56

Their product = 54 x 2 = 108

4 0
3 years ago
Read 2 more answers
(08.07 HC)
andreev551 [17]

Answer:

\textsf{A)} \quad x=-2, \:\:x=\dfrac{5}{2}

\textsf{B)} \quad \left(\dfrac{1}{4},-\dfrac{81}{8}\right)=(0.25,-10.125)

C)  See attachment.

Step-by-step explanation:

Given function:

f(x)=2x^2-x-10

<h3><u>Part A</u></h3>

To factor a <u>quadratic</u> in the form  ax^2+bx+c<em> , </em>find two numbers that multiply to ac and sum to b :

\implies ac=2 \cdot -10=-20

\implies b=-1

Therefore, the two numbers are -5 and 4.

Rewrite b as the sum of these two numbers:

\implies f(x)=2x^2-5x+4x-10

Factor the first two terms and the last two terms separately:

\implies f(x)=x(2x-5)+2(2x-5)

Factor out the common term  (2x - 5):

\implies f(x)=(x+2)(2x-5)

The x-intercepts are when the curve crosses the x-axis, so when y = 0:

\implies (x+2)(2x-5)=0

Therefore:

\implies (x+2)=0 \implies x=-2

\implies (2x-5)=0 \implies x=\dfrac{5}{2}

So the x-intercepts are:

x=-2, \:\:x=\dfrac{5}{2}

<h3><u>Part B</u></h3>

The x-value of the vertex is:

\implies x=\dfrac{-b}{2a}

Therefore, the x-value of the vertex of the given function is:

\implies x=\dfrac{-(-1)}{2(2)}=\dfrac{1}{4}

To find the y-value of the vertex, substitute the found value of x into the function:

\implies f\left(\dfrac{1}{4}\right)=2\left(\dfrac{1}{4}\right)^2-\left(\dfrac{1}{4}\right)-10=-\dfrac{81}{8}

Therefore, the vertex of the function is:

\left(\dfrac{1}{4},-\dfrac{81}{8}\right)=(0.25,-10.125)

<h3><u>Part C</u></h3>

Plot the x-intercepts found in Part A.

Plot the vertex found in Part B.

As the <u>leading coefficient</u> of the function is positive, the parabola will open upwards.  This is confirmed as the vertex is a minimum point.

The axis of symmetry is the <u>x-value</u> of the <u>vertex</u>.  Draw a line at x = ¹/₄ and use this to ensure the drawing of the parabola is <u>symmetrical</u>.

Draw a upwards opening parabola that has a minimum point at the vertex and that passes through the x-intercepts (see attachment).

5 0
2 years ago
The current value of a baseball card is 60 times its original value v
jeka94
60v = $15

60v/60 = $15/60

v = 0.25

The original value of the baseball card is $0.25
5 0
3 years ago
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