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djverab [1.8K]
3 years ago
12

Which of the statements is true regarding the graphed functions ?

Mathematics
1 answer:
DedPeter [7]3 years ago
6 0
F(x) means the function defined at that x value. It really just means what y value when x is equal to that input. So we can see clearly that A is false. They’re nearly opposite y values. B is also obviously false since the y values aren’t equal. C is the same case, the y values aren’t equal. D is true. When x = -2 for both functions, we can see the y value is the same. They also intercept, so that’s a pretty dead giveaway

D.)
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Determine the standard form of the equation of the line that passes through (-6,6) and (3,-2)
Simora [160]

Answer:

y=(8/9)x + 4 and 2/3

Step-by-step explanation:

the slope of this line:

change in y/change in x

change in y=6-(-2)=8

change in x=-6-3=-9

change in y/change in x= 8/9

8/9 is the slope, so you plug it in for m in the standard form equation. You then use one point's x and y values to substitute for x and y in the equation, and solve for b, which is the y intercept

y=mx+b

y=(8/9)x+b

-2=(8/9)*3+b

-2=8/3+b

-4 and 2/3=b

4 0
3 years ago
Simplify (3-6i) (-5+ i)
Tanya [424]

Answer:

Simplifed using FOIL: -15+30t+(3-6t)i

Simplifed using distributive property: 15+30t+(3-6t)i

Step-by-step explanation:

5 0
3 years ago
Find the solution to the initial value problem (1 + x^{5}) y' + 5 x^{4} y = 5 x^{8}
natali 33 [55]
(1+x^5)y'+5x^4y=5x^8
\bigg((1+x^5)y\bigg)'=5x^8
(1+x^5)y=5\displaystyle\int x^8\,\mathrm dx
(1+x^5)y=\dfrac59x^9+C
y=\dfrac{5x^9+C}{9(1+x^5)}
8 0
3 years ago
John has a map that shows a rectangular park 1 1/4 cm : 8 yd. on the map, the width of the park is 2 1/2 cm. What is the parks a
Ber [7]

Answer:

16 yd.  This is the park's actual length.

Step-by-step explanation:

Write and solve an equation of ratios:

1 1/4 cm     8 yd

------------ = -----------

2 1/2 cm        x

Note that 2(1 1/4 cm) = 2 1/2 cm, so the above equation becomes:

 1       8 yd

----- = ---------

  2         x

Solving for x, we get x = 16 yd.  This is the park's actual length.

3 0
3 years ago
Last one!! I need the steps please! Will mark brainliest!
hoa [83]

Answer:

h(t)=-6(t-2)^2+24

Step-by-step explanation:

Given function:

h(t)=-6t^2+24t

where:

  • h = height (in feet)
  • t = times (in seconds)

Rewrite in the form h(t)=a(t-h)^2+k

The quickest way to do this is to expand h(t)=a(t-h)^2+k and compare coefficients with the original function.

\begin{aligned}h(t)& =a(t-h)^2+k\\ & = at^2-2aht+ah^2+k\end{aligned}

Comparing coefficients with h(t)=-6t^2+24t

\begin{aligned}\implies at^2& =-6t^2\\ a &=-6\end{aligned}

\begin{aligned}\implies -2aht & =24t\\ -2(-6)ht& =24t\\ 12ht & = 24t\\ 12h & = 24\\ h & = 2\end{aligned}

\begin{aligned}\implies ah^2+k & = 0\\(-6)(2)^2+k &=0\\ -24+k & =0\\ k &=24 \end{aligned}

Therefore, substituting the found values into the equation:

h(t)=-6(t-2)^2+24

6 0
2 years ago
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