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Archy [21]
3 years ago
8

What volume (in mL ) of 0.200   M NaOH do we need to titrate 40.00 mL of 0.140   M HBr to the equivalence point?

Chemistry
2 answers:
Ugo [173]3 years ago
7 0
NaOH + HBr =⇒ NaBr + H2O

35.0 ml HBr x 1 liter/1000 mL x 0.140 moles HBr/ liter = 0.0049 moles HBr

0.0049 moles HBr x 1mole NaOH/1mole HBr = 0.0049 moles HBr

0.0049 moles HBr x 1 liter NaOH/0.200 moles NaOH x 1000 mL/1liter= 24.5 mL NaOH
MakcuM [25]3 years ago
7 0

Answer: 28 ml

Explanation: HBr+NaOH\rightarrow NaBr+H_2O

At equivalence point the number of H^+ ions is equal the number of  OH^- ions and thus the acid has been completely neutralized by the base.

M_1V_1=M_2V_2

M_1 = molarity of acid

V_1 = volume of acid

M_2 = molarity of base

V_2 = volume of base

0.140\times 40ml=0.200\times V_2

V_2=28ml

Thus 28 ml of 0.200 M NaOH are needed to titrate 40.00 mL of 0.140 M HBr to the equivalence point.

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There are 1.2 x 1024 formula units
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A chemist is using 341 milliliters of a solution of acid and water. If 15.8% of the solution is acid, how many milliliters of ac
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3 years ago
Consider the KF molecule, which has an ionic bond. The bond length is 2.17 x 1010 m (a) Calculate the energy required to dissoci
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a) +640 kJ/mol or +1.06x10⁻¹⁸ J

b) +276 kJ/mol

Explanation:

To dissociate the molecule, the bond must be broken, thus, it's necessary energy equal to the energy of the bond, which can be calculated by:

E = (Q1*Q2)/(4*π*ε*r)

Where Q is the charge of the ions, ε is a constant (8.854x10⁻¹²C²J ⁻¹ m⁻¹), and r is the bond length. Each one of the ions has a charge equal to 1. The elementary charge is 1.602x10⁻¹⁹C, which will be the charge of them.

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498 = 640 - (418 - EA)

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222 + EA = 498

EA = +276 kJ/mol

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