T = 5, so after 5 years
p(t) = t^3 - 14t^2 + 20t + 120
Take derivative to find minimum:
p’(t) = 3t^2 - 28t + 10
Factor to solve for t:
p’(t) = (3t - 2)(t - 5)
0 = (3t - 2)(t - 5)
0 = 3t - 2
2 = 3t
2/3 = t
Plug 2/3 into original equation, this is a maximum. We want the minimum:
0 = t - 5
5 = t
Plug back into original:
5^3 - 14(5)^2 + 20(5) + 120
125 - 14(25) + 100 + 120
125 - 350 + 220
- 225 + 220
p(5) = -5
You add the numerators and keep it over the denominator. 4/16 plus 12/16 is 16/16 and when the same number is the denominator and numerator at the same time, its 1
1
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Answer:
c
Step-by-step explanation:
Answer:
-9 = 0.45m
Step-by-step explanation:

- ^ Subtract 0.45m from BOTH sides. so
... etc - Why? So that we can make the equation less complicated. Our goal is to isolate the variable m to be on one side of the "=" sign by itself
- That will equal to:
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