1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Elis [28]
3 years ago
10

A car dealership earns a portion of its profit on the accessories sold with a car. The dealer sold a Toyota Camry loaded with ac

cessories for $24,000. The total cost of the car was 8 times as much as the accessories. How much did the accessories cost?
Mathematics
2 answers:
WINSTONCH [101]3 years ago
4 0
$24000/8 = $3000
The accessories cost $3000
Tom [10]3 years ago
4 0

Answer:

$2666.67

Step-by-step explanation:

We are given that

Selling price of car with accessories=$24000

We have to find the value of cost of accessories

Let cost of accessories=x

Total cost of car =y

Total cost of car=8 times the accessories

Total cost of car =y=8 x

According to question

Selling price=Cost of car +cost of accessories

$2400=y+x

Substitute the values

8x+x=$2400

9x=24000

x=\frac{24000}{9}

x=$2666.67

Hence, the cost of accessories=$2666.67

You might be interested in
Quantitative data
wariber [46]
The answer is A) measures things using quantities or numbers. Hope this helps!
8 0
3 years ago
Determine whether the given vectors are orthogonal, parallel or neither. (a) u=[-3,9,6], v=[4,-12,-8,], (b) u=[1,-1,2] v=[2,-1,1
nevsk [136]

Answer:

a) u v= (-3)*(4) + (9)*(-12)+ (6)*(-8)=-168

Since the dot product is not equal to zero then the two vectors are not orthogonal.

|u|= \sqrt{(-3)^2 +(9)^2 +(6)^2}=\sqrt{126}

|v| =\sqrt{(4)^2 +(-12)^2 +(-8)^2}=\sqrt{224}

cos \theta = \frac{uv}{|u| |v|}

\theta = cos^{-1} (\frac{uv}{|u| |v|})

If we replace we got:

\theta = cos^{-1} (\frac{-168}{\sqrt{126} \sqrt{224}})=cos^{-1} (-1) = \pi

Since the angle between the two vectors is 180 degrees we can conclude that are parallel

b) u v= (1)*(2) + (-1)*(-1)+ (2)*(1)=5

|u|= \sqrt{(1)^2 +(-1)^2 +(2)^2}=\sqrt{6}

|v| =\sqrt{(2)^2 +(-1)^2 +(1)^2}=\sqrt{6}

cos \theta = \frac{uv}{|u| |v|}

\theta = cos^{-1} (\frac{uv}{|u| |v|})

\theta = cos^{-1} (\frac{5}{\sqrt{6} \sqrt{6}})=cos^{-1} (\frac{5}{6}) = 33.557

Since the angle between the two vectors is not 0 or 180 degrees we can conclude that are either.

c) u v= (a)*(-b) + (b)*(a)+ (c)*(0)=-ab +ba +0 = -ab+ab =0

Since the dot product is equal to zero then the two vectors are orthogonal.

Step-by-step explanation:

For each case first we need to calculate the dot product of the vectors, and after this if the dot product is not equal to 0 we can calculate the angle between the two vectors in order to see if there are parallel or not.

Part a

u=[-3,9,6], v=[4,-12,-8,]

The dot product on this case is:

u v= (-3)*(4) + (9)*(-12)+ (6)*(-8)=-168

Since the dot product is not equal to zero then the two vectors are not orthogonal.

Now we can calculate the magnitude of each vector like this:

|u|= \sqrt{(-3)^2 +(9)^2 +(6)^2}=\sqrt{126}

|v| =\sqrt{(4)^2 +(-12)^2 +(-8)^2}=\sqrt{224}

And finally we can calculate the angle between the vectors like this:

cos \theta = \frac{uv}{|u| |v|}

And the angle is given by:

\theta = cos^{-1} (\frac{uv}{|u| |v|})

If we replace we got:

\theta = cos^{-1} (\frac{-168}{\sqrt{126} \sqrt{224}})=cos^{-1} (-1) = \pi

Since the angle between the two vectors is 180 degrees we can conclude that are parallel

Part b

u=[1,-1,2] v=[2,-1,1]

The dot product on this case is:

u v= (1)*(2) + (-1)*(-1)+ (2)*(1)=5

Since the dot product is not equal to zero then the two vectors are not orthogonal.

Now we can calculate the magnitude of each vector like this:

|u|= \sqrt{(1)^2 +(-1)^2 +(2)^2}=\sqrt{6}

|v| =\sqrt{(2)^2 +(-1)^2 +(1)^2}=\sqrt{6}

And finally we can calculate the angle between the vectors like this:

cos \theta = \frac{uv}{|u| |v|}

And the angle is given by:

\theta = cos^{-1} (\frac{uv}{|u| |v|})

If we replace we got:

\theta = cos^{-1} (\frac{5}{\sqrt{6} \sqrt{6}})=cos^{-1} (\frac{5}{6}) = 33.557

Since the angle between the two vectors is not 0 or 180 degrees we can conclude that are either.

Part c

u=[a,b,c] v=[-b,a,0]

The dot product on this case is:

u v= (a)*(-b) + (b)*(a)+ (c)*(0)=-ab +ba +0 = -ab+ab =0

Since the dot product is equal to zero then the two vectors are orthogonal.

5 0
3 years ago
Read 2 more answers
Assume you have a poker chip set containing blue, red, and white chips, all of the same size. You place 30 blue chips, 20 red ch
Zigmanuir [339]

Answer:

0.3

Step-by-step explanation:

30/(30+20+50) = 30/100 = 0.3

3 0
3 years ago
What is 4.110 in word form
irga5000 [103]
Four and Eleven Hundredth 
7 0
4 years ago
What is the length of each side of the triangle given a perimeter of 45 cm?
gladu [14]
TO find perimeter you add all sides. But to find the totaly of each side, you will divide. So a triangle has 3 sides, so you divide 45 by 3 to get the sides length of:
15 cm each
~hope this helped :)
6 0
3 years ago
Read 2 more answers
Other questions:
  • What is x2 – 6 = 16x + 30 rewritten in standard form, then factored?
    14·2 answers
  • What is the greatest common factor of 15 and 65
    12·2 answers
  • You need to multiply n by a power of 10 to help you find the fraction?
    13·1 answer
  • A theatre holds 1200 people when full.If it is 80% full,how many people are present
    8·1 answer
  • I need help with number 2
    14·1 answer
  • What is the Greatest Common Factor of 542<br> and 18?
    9·1 answer
  • What is the slope of the line that passes through
    6·1 answer
  • Rewrite to the algebraic form The product of x and 4.​
    7·2 answers
  • Forty nine minus twenty five b squared in factored form
    6·2 answers
  • How do you solve this algebreically?<br> 3/8=x/20
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!