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wel
3 years ago
14

Does y=5x squared+2x-1 have a min or max

Mathematics
1 answer:
Mnenie [13.5K]3 years ago
6 0

Step-by-step explanation:

y = 5x^2 + 2x - 1

The maximum degree of polynomial is 2 expressed by 5x^2.

The min is -1.

<h3><u><em></em></u></h3><h3><u><em></em></u></h3><h3><u><em>Hope this helps!!</em></u></h3><h3><u><em>: )</em></u></h3>
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Solve the equation by completing the square m^2+6m-77=-5
Grace [21]
Maybe you thought about this:
m^2+6m-77+5=0 => m^2+6m-72=0 => m^2+ 2*3*m+3^2-3^2-72=0
=> m^2+2*3*x+3^2= (m+3)^2 this is the complete square of the binomial, we will still keep it =>
(m+3)^2 -9 -72=0 => (m+3)^2 - 81 = 0 => (m+3)^2 - 9^2 = 0
Now we got the difference squares, it mean a^2 - b^2 = (a-b) (a+b)
In according to this => (m+3-9) (m+3+9) = 0 =>
(m-6) (m+12)=0 => m-6=0 or m+12=0 => m1=6 or m2= -12 !!!!
Are you satisfied with this solution?

6 0
3 years ago
Plz help I am very confused I need help now plz
dexar [7]

Answer:

-21

remember that when there is a positive and negative sign the product will always be negative

6 0
3 years ago
Find the value of the expression:<br>70–a2 for a=–25; 1; 10
shutvik [7]

Simple answer.

You will have to replace a, with the given numbers.

For the 1st one)

70-25² since a=25. 70-625=-55

2nd)

70-1²=70-1=69

3d)

70-10²=70-100=-30

Hope this helped.

8 0
3 years ago
Let h(t) be the height of the tide at the Bay of Fundy in meters that has changed since midnight, with t measured in hours. We r
Vsevolod [243]

Answer and Step-by-step explanation:

a) h(7) = 2.75 metre

This means that the change in height of tide at Bay of Fundy 7 hrs after midnight is 2.75 meters. That is, putting t=7 hours into the function h(t) will give the change in height of the tide at Bay of Fundy since midnight.

b) h'(7) = 0.21 metres/hour

The h' sign indicates the first derivative of the function h(t). Since h(t) gives the change in height of tide at Bay of Fundy since midnight, h'(t) will give the rate of change of the height of tide at Bay of Fundy since midnight with time. That is, how fast or how slow the height of tide at Bay of Fundy since midnight is changing.

h'(7) = 0.21 m/h means the rate of change of the height of tide at Bay of Fundy 7 hours after midnight is 0.21 metres/hour.

c) h⁻¹(-1.5) = 13.2

The inverse of a function is defined as the function that completely undo the effect of the original function.

The original function takes a value of time and gives the height of tide at Bay of Fundy since midnight, but the inverse now would take the height of tide at Bay of Fundy since midnight and give the value of time that corresponds to such a height.

h⁻¹(-1.5) = 13.2 hours means that the time, measured from midnight, that it takes the height of tide at Bay of Fundy to change by -1.5 m since midnight is 13.2 hours.

d) (h⁻¹)'(-1.5) = -1.6 hour/metre

Since we have previously established that the inverse of the function, h⁻¹ is the function that gives the value of time that corresponds to a particular change in height of tide at Bay of Fundy since midnight.

So, the derivative of that inverse function would give the how much the time (Since midnight) is changing with respect to the change of the height of tide at Bay of Fundy since midnight.

(h⁻¹)'(-1.5) = -1.6 hour/metre means that, at change of height = -1.5 m, the time for this change to occur is changing at a rate of -1.6 hours/metre

5 0
3 years ago
What is 92.583 rounded to the nearest tenth
Stolb23 [73]
92.583 is rounded to 92.6
8 0
3 years ago
Read 2 more answers
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