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Digiron [165]
3 years ago
14

in a recent year,the untited states census bureau reported that 0.3 percent of the population in the united States was Japanese.

write this percent as a decimal and as a fraction then interpret its meaning as a ratio of the united States population.(I need this now)
Mathematics
1 answer:
Leya [2.2K]3 years ago
5 0
It is 00.3 as a decimal
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If Neil Works 3/4 of an hour on Monday and 6/10 of an hour on Tuesday how much time will she work altogether?
jek_recluse [69]

Answer:

C

Step-by-step explanation:

3/4 + 6/10

Find a common denominator and find what you multiply to each denominator to get that number and multiply the numerator by the same amount

(3/4 * 5/5) + (6/10 * 2/2)=

15/20 + 12/20

Then add

15/20 + 12/20= 27/20

Then finally convert to mixed number

27/20 = 1 7/20

7 0
3 years ago
Eugene wants to buy jeans at a store that is offering a $10 discount on every item. The tag on the jeans is marked 50% off. The
kifflom [539]
A. $14.99 .. do $49.98/2 = $24.99 and then subtract $10.
B. $19.99 .. do $49.98-19 = $39.98 and then divide it by 2.
3 0
3 years ago
The variables y and x have a proportional relationship, and y =5 when x=4
patriot [66]

Answer:The value of x is 6.4

Step-by-step explanation:

5/8=4/x use cross product.

5x=32 divide both sides by 5

x = 6.4

3 0
3 years ago
If x+1/x=7,find x^2+1/x^2​
trapecia [35]

Answer:

x²+1/x² = 51

Explanation:

Given x - 1/x = 7 ---(1)

We know the algebraic identity:

a²+b²-2ab = (a-b)²

Or

a²+b² = (a-b)²+2ab

Now,

x²+1/x²

= (x-1/x)²+2*x*(1/x)

= (x-1/x)²+2

:7²+2 [ from (1)] =

= 49+2

= 51

Therefore,

x²+1/x² = 51

3 0
3 years ago
Find the critical numbers of the function f(x) = x6(x − 1)5 what does the first derivative test tell you that the second derivat
patriot [66]
The given function is f(x) = x⁶(x-1)⁵

The first derivative is
f'(x) = 6x⁵(x-1)⁵ + 5x⁶(x-1)⁴
       = x⁵(x-1)⁴(6x - 6 + 5x)
       = x⁵(x-1)⁴(11x - 6)
The critical values are the zeros of f'(x). They are
x = 0, 6/11, and 1.
The critical values indicate that turning points exist for f(x) at the critical points. However, we do not know the nature of the turning points.

Write the first derivative in the form f'(x) = (x-1)⁴(11x⁶ - 6x⁵).
The second derivative is
f''(x) = 4(x-1)³(11x⁶ - 6x⁵) + (x-1)⁴(66x⁵ - 30x⁴)
        = (x-1)³(44x⁶ - 24x⁵ + 66x⁶ - 30x⁵ - 66x⁵ + 30x⁴)
        = (x-1)³(110x⁶ - 120x⁵ + 30x⁴)
        = 10x⁴(x-1)³(11x² - 12x + 3)
The sign of f''(x) at the critical values tell us the nature of the turning point.

f''(0) = 0, therefore a point of inflection exists at x = 0.
f''(6/11) > 0, therefore a local minumum exists at x = 6/11.
f''(1) = 0, therefore a point of inflection exists at x=1.

The graphs shown below confirm these results.

8 0
3 years ago
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