Answer:
The diagram of the plotting point 
is attached below.
Step-by-step explanation:
Given the points
as
so the point can be visualized as:
Now, we can check the point x = 3.5, and determine the corresponding value y = 2.75 and plot the point at the location (x, y) = (3.5, 2.75)
The diagram of the plotting point is attached below.
Answer:
-2
Step-by-step explanation:
Just use 6-8 and you will get - 2
Check again with - 2+8 you will get positive 6
<u>Answer:</u>
<h2><u>-2.25</u></h2><h3>
<u>Step-by-step explanation:</u></h3>
Lets start with D:
It says, 0.43 but we're on the OPPOSITE of 0, so it can't be a positive number.
Same goes for C.
Now we are on to our last two.
B, is -2.5 and A, is -0.8
So, now we look at the point <em>B </em>and <em>assume</em>, because it says Select a reasonable value for Point B.
To me, point <em>B </em>looks to be about around -2.0
So, the <em>reasonable value </em>for this problem would be -2.25
Answer:
C
Step-by-step explanation:
Its C because its x (a variable) and is costanly changing
Answer:
<h2>X = 0</h2><h2>Y = 1</h2>
First of all, observe that this is a line, since you can rewrite the equation as y−x+1=0 , which follows the pattern of the generic line ax+by+c=0 .
To draw a line you need two of its points, which you can connect.
To find two points, you can plug any value for one variable, and solve for the other.
For example, let's choose
x=0 . The equation becomes
0−1=y , and so y=−1 .
The first point is thus (0,−1).
Then, let's choose
x=1 . The equation becomes 1−1=y , and so y=0 . The first point is thus
(1,0).
Now you only need to draw the points
(0,−1)
Step-by-step explanation:
Hope it is helpful...
