Cos Ф - cos Ф.sin² Ф
sin² Ф = 1 - cos² Ф
cos Ф - cos Ф( 1-cos² Ф) = cos Ф - cos Ф - cos³ Ф = cos³ Ф
cos Ф - cos Ф.sin² Ф = cos³ Ф
Answer:
14,793
Step-by-step explanation:
Answer:
h(x)
Step-by-step explanation:
to solve for an inverse, you swap the x and the y and then solve for y
f(x) = 4x^3-8
y = 4x^3 - 8
x = 4y^3 - 8 swap the x and y
now solve for y:
x + 8 = 4y^3
(x + 8)/4 = y^3
1/4x + 8/4 = y^3
1/4x + 2 = y^3
y = ![\sqrt[3]{1/4x + 2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B1%2F4x%20%2B%202%7D)
Answer:
m < -
Step-by-step explanation:
8m + 95 < -87m + 5
8m + 87m < 5 - 95
95m < -90
m < -<u>
</u>
Simplifying gives;
m < -
Hi!
So the original formula for a problem likes this or a quadratic is:
ax^2 + bx+ c
so a is the accelaration; b is the initial velocity; and c is the initial height
so none of those are the zeros, which means c is out
zeros are the x values when y is 0, that also means when the parabola crosses the x axis
so d is out too because the maximum height is the vertex which mean that there would probably be a y value. in some cases the vertex is the zero, but not here
B is out because x isn't time it is distance
your answer is A!
Hope this helps!
