How many moles are in 1.9 x 10^25 molecules of carbon dioxide

1 answer:

4 0

1 mole ----------- 6.02x10²³ molecules
? moles --------- 1.9x10²⁵ molecules

moles = 1.9 x 10²⁵ * 1 / 6.02x10²³

= 1.9 x 10²⁵ / 6.02x10²³

= 31.561 moles

hope this helps!

You might be interested in

The offspring of sexual reproduction typically ----.

Licemer1 [7]

I think that the correct answer is D- gets half from each parent

3 0

3 years ago

Show the equation how many grams of Mg(OH)2 would be produced from 4 mol KOH?

Sindrei [870]

Mole ratio:

MgCl₂ + 2 KOH = Mg(OH)₂ + 2 KCl

2 moles KOH ---------------- 1 mole Mg(OH)₂
4 moles KOH ------------------- moles Mg(OH)₂

moles Mg(OH)₂ = 4 x 1 / 2

= 2 moles of   Mg(OH)₂

molar mass Mg(OH)₂ = 58g/mol

mass of   Mg(OH)₂ = n x mm

mass of  Mg(OH)₂ = 58 x 2

= 116 g of <span> Mg(OH)₂</span>

hope this helps!

8 0

2 years ago

(d) carbon monoxide

Irina18 [472]

Answer:

D. carbon monoxide

Hope this helps :)

6 0

2 years ago

A solution is made containing 4.6 g of sodium chloride per 250g of water.

lozanna [386]

Answer:

$\large \boxed{1.81 \, \%}$

Explanation:

$\text{Mass percent} = \dfrac{\text{mass of solute} }{\text{mass of solution}} \times 100 \, \%$

Data:

Mass of NaCl = 4.6 g

Mass of water = 250 g

Calculations:

Mass of solution = mass of NaCl + mass of water = 4.6 g + 250 g = 254.6 g.

$\text{\% m/m} = \dfrac{\text{4.6 g} }{\text{254.6 g}} \times 100 \, \% = \mathbf{1.81 \, \%}\\\\\text{The percent by mass of NaCl is $\large \boxed{\mathbf{1.81 \, \%}}$}$

3 0

3 years ago

A recently depolarized area of a cell membrane cannot generate an action potential because of the

marysya [2.9K]

The refractory period makes the cell rest. In this period, the cell becomes able to depolarize again by collecting ions.

4 0

3 years ago

Read 2 more answers