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Hatshy [7]
3 years ago
10

HELP PLZ ASAP... I'M CONFUSED :(

Chemistry
2 answers:
taurus [48]3 years ago
8 0

B. In forward-biased setup, large numbers of charge carriers will be pulled across the junction and result in a large current.

Snowcat [4.5K]3 years ago
6 0
D. In forward-biased setup, large numbers of charge carriers will be pulled across the junctions and result in a large current
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Answer:

why are anime and cartoons awesome? wt..f

Explanation:

I dont got that are you serious or making fun?

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The amount of a harmful chemical to which a person is exposed is the ____.
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A. dose
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An archaeologist graduate student found a leg bone of a large animal during the building of a new science building. The bone had
Vlad [161]

Answer : The time passed in years is 2.74\times 10^2\text{ years}

Explanation :

Half-life of carbon-14 = 5730 years

First we have to calculate the rate constant, we use the formula :

k=\frac{0.693}{t_{1/2}}

k=\frac{0.693}{5730\text{ years}}

k=1.21\times 10^{-4}\text{ years}^{-1}

Now we have to calculate the time passed.

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  = 1.21\times 10^{-4}\text{ years}^{-1}

t = time passed by the sample  = ?

a = initial amount of the reactant disintegrate = 15.3

a - x = amount left after decay process = 14.8

Now put all the given values in above equation, we get

t=\frac{2.303}{1.21\times 10^{-4}}\log\frac{15.3}{14.8}

t=274.64\text{ years}=2.74\times 10^2\text{ years}

Therefore, the time passed in years is 2.74\times 10^2\text{ years}

4 0
3 years ago
7. A 26.4-ml sample of ethylene gas, C2H4, has a pres-sure of 2.50 atm at 2.5°C. If the
never [62]

Answer: 1.87 atm

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 2.50 atm

P_2 = final pressure of gas = ?

V_1 = initial volume of gas = 26.4 ml

V_2 = final volume of gas = 36.2 ml

T_1 = initial temperature of gas = 2.5^oC=273+2.5=275.5K

T_2 = final temperature of gas = 10^oC=273+10=283K

Now put all the given values in the above equation, we get:

\frac{2.50\times 26.4}{275.5}=\frac{P_2\times 36.2}{283}

P_2=1.87atm

The new pressure is 1.87 atm by using combined gas law.

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How does the temperature of the air change with altitude?
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