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iragen [17]
2 years ago
10

What type of weathering will occur more rapidly in an area with extremely cold winters and hot summers?

Chemistry
2 answers:
Novosadov [1.4K]2 years ago
3 0

Answer:

mechanical weathering through the process of ice wedging

Explanation:

Troyanec [42]2 years ago
3 0

Answer:

In cold climates, the freezing and thawing that occurs causes rapid mechanical weathering through the process of ice wedging. In warmer climates, chemical weathering is more rapid because the chemical reactions that dissolve rocks and minerals are accelerated by warm temperatures.

Explanation:

:)

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a block of iron has the dimensions of 3.00 cm x 3.00 cm x 3.00 cm. it has a mass of 213 g. what is its density? a. 638 g/cm3 b.
Juliette [100K]
Volume = 3 cm × 3cm × 3cm
             =  27 cm ³

Mass  =  213 g

Density  =  \frac{MASS}{VOLUME}
 
              = <span>\frac{213 g}{27 cm ^{3} }
</span> 
<span>              =  7.89 g / cm³

Thus answer is D.</span>
8 0
3 years ago
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What is the difference between polyatomic and monatomic compounds??
Klio2033 [76]

Answer:

Monatomic ions are made up of only one atom per ion, whereas polyatomic ions are made up of numerous atoms per ion.

Explanation:

6 0
2 years ago
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(Thermodynamics)
frutty [35]

Answer:

3853 g

Step-by-step explanation:

M_r: 107.87

         16Ag + S₈ ⟶ 8Ag₂S; ΔH°f =  -31.8 kJ·mol⁻¹

1. Calculate the moles of Ag₂S

Moles of Ag₂S = 567.9 kJ × 1 mol Ag₂S/31.8kJ = 17.858 mol Ag₂S

2. Calculate the moles of Ag

Moles of Ag = 17.86 mol Ag₂S × (16 mol Ag/8 mol Ag₂S) = 35.717 mol Ag

3. Calculate the mass of Ag

Mass of g = 35.717 mol Ag × (107.87 g Ag/1 mol Ag) = 3853 g Ag

You must react 3853 g of Ag to produce 567.9 kJ of heat

3 0
3 years ago
How many milliliters of a 1.5 m h2so4 are needed to neutralize 35ml sample of a 1.5 m solution?
DochEvi [55]

Answer:

1) 17.5 mL

Explanation:

Hello,

In this case, the reaction between sulfuric acid and potassium hydroxide is:

H_2SO_4+2KOH\rightarrow K_2SO_4+2H_2O

In such a way, we notice a 1:2 molar ratio between the acid and the base, therefore, at the equivalence point we have:

2*n_{acid}=n_{base}

And in terms of concentrations and volumes:

2*M_{acid}V_{acid}=M_{base}V_{base}

Thus, we solve for the volume of acid:

V_{acid}=\frac{M_{base}V_{base}}{2*M_{acid}} =\frac{35mL*1.5M}{2*1.5M} \\\\V_{acid}=17.5mL

Best regards.

5 0
3 years ago
For each scenario, determine if the electron has absorbed energy or emitted energy,
k0ka [10]

Answer:

1) emitted energy

2)absorbed energy

3)absorbed energy

4)emitted energy

Explanation:

I just got it right

7 0
3 years ago
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