The molecule that contains a total of eight carbon atoms :
b. 2-methyl-heptane
formula of 2-methyl-heptane
C8H18 ( or CH3CH(CH3)CH2(CH2)3CH3 rather )
hope this help
Answer:
0.165 mol·L⁻¹
Explanation:
1. Write the <em>chemical equation</em> for the reaction.
HNO₃ + KOH ⟶ KNO₃ + H₂O
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2. Calculate the <em>moles of HNO₃</em>
c = n/V Multiply each side by V and transpose
n = Vc
V = 0.027 86 L
c = 0.1744 mol·L⁻¹ Calculate the moles of HNO₃
Moles of HNO₃ = 0.027 86 × 0.1744
Moles of HNO₃ = 4.859 × 10⁻³ mol HNO₃
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3. Calculate the <em>moles of KOH
</em>
1 mol KOH ≡ 1 mol HNO₃ Calculate the moles of KOH
Moles of KOH = 4.859 × 10⁻³× 1/1
Moles of KOH = 4.859 × 10⁻³ mol KOH
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4. Calculate the <em>molar concentration</em> of the KOH
V = 29.4 mL = 0.0294 L Calculate the concentration
c = 4.859 × 10⁻³/0.0294
c = 0.165 mol·L⁻¹
explanation: Synthetic fiber or synthetic fibre (in British English; see spelling differences) are fibers made by humans through chemical synthesis, as opposed to natural fibers that are directly derived from living organisms. They are the result of extensive research by scientists to improve upon naturally occurring animal and plant fibers. In general, synthetic fibers are created by extruding fiber-forming materials through spinnerets, forming a fiber. These are called synthetic or artificial fibers. Synthetic fibers are created by a process known as polymerization, which involves combining monomers to make a long chain or polymer. The word polymer comes from a Greek prefix "poly" which means "many" and suffix "mer" which means "single units". (Note: each single unit of a polymer is called a monomer). There are two types of polymerization: linear polymerization and cross-linked polymerization.
Answer:
Explanation:
the raw noodles are thin and long, and the pins are sharp. The beads are round, and the salt is grainy. To seperate them, take out the safety pins with a magnet, then the noodles, then the beads. Leave the salt. Then BOOM. They are seperated.
Explanation:
1 moles Lead(II) Acetate to grams = 325.28804 grams
3.47 moles Lead(II) Acetate to grams = 325.28804 ×3.47 grams=1128.749 grams
1 moles sodium chloride to grams=58.5 grams
3.47 moles sodium chloride to grams=58.5×3.47 grams
=202.995 grams
