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Serjik [45]
3 years ago
8

PLEASEEE PLEASEEE HELP

Chemistry
1 answer:
kati45 [8]3 years ago
3 0

Answer:

= 49.674 g NaCl

Explanation:

From the equation;

1 mole of Sodium metal produces 2 moles sodium chloride

This means;

23 g of Na will produce 116.88 g of NaCl

Therefore;

11.5 g will generate;

 = (11.5 × 116.88)/23

 =  58.44 g of NaCl

But;

Percentage yield = (Actual yield/Theoretical yield)× 100%

         85 /100 = Actual yield /58.44 g

Thus;

Actual yield = 0.85 × 58.44

                  = 49.674 g NaCl

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The decomposition of ammonia is characterized by the following decomposition equation:
                                  2NH₃<span>   →   N</span>₂  <span> +   3H</span>₂   

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    If the number of moles of N₂  =  0.0351 mol
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