Solubility is a chemical property referring to the ability for a given substance, the solute, to dissolve in a solvent. It is measured in terms of the maximum amount of solute dissolved in a solvent at equilibrium. ... The solvent is often a solid, which can be a pure substance or a mixture.

Explanation:

5 0

3 years ago

4Na + O2 2Na2O

beks73 [17]

4
N
a
+
O
2
→
2
N
a
2
O
.
By the stoichiometry of this reaction if 5 mol natrium react, then 2.5 mol
N
a
2
O
should result.
Explanation:
The molecular mass of natrium oxide is
61.98

g
⋅
m
o
l
−
1
. If
5

m
o
l
natrium react, then
5
2

m
o
l
×
61.98

g
⋅
m
o
l
−
1

=

154.95

g
natrium oxide should result.
So what have I done here? First, I had a balanced chemical equation (this is the important step; is it balanced?). Then I used the stoichiometry to get the molar quantity of product, and converted this molar quantity to mass. If this is not clear, I am willing to have another go

5 0

3 years ago

V2 = (P1 × V1 × T2) (P2 × T1) A gas with a beginning pressure of 2 atm at a temperature of 300 K has a volume of 20 ml. What wil

rusak2 [61]

6.6ml will be the new volume if the pressure increases to 4 atm and the temperature are lowered to 200 K.

<h3>What is an ideal gas equation?</h3>

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

Given data:

$V_1=20 ml$

$T_1=3$

$P_1=2 atm$

$T_2=200 K$

$P_2=4 atm$

$V_2=?$

Using equation:

$V_2 =$ $\frac{P_1 X V_1 XT_2}{P_2 X T_1}$

$V_2 =$ $\frac{2 atm X 20 ml X200 K}{4 atm X 300 K}$

$V_2 = 6.6 ml$

Hence, 6.6ml will be the new volume if the pressure increases to 4 atm and the temperature are lowered to 200 K.

Learn more about the ideal gas equation here:

#SPJ1

6 0

2 years ago

One disadvantage of burning propane (C3H8) is that carbon dioxide is one of the products. The released CO2 increases the growing

Hoochie [10]

Answer:

80 MOLES OF WATER ARE PRODUCED WHEN 20 MOLES OF PROPANE ARE BURNED IN EXCESS OXYGEN ON A GAS GRILL.

Explanation:

Equation for the reaction:

C3H8 + 5 O2 ---------> 4 H2O + 3 CO2 + Heat

The above equation is in the presence of excess oxygen.

In this reaction,

1 mole of propane forms 4 moles of H2O

If 20 moles of propane were to be used, how many moles of water will be produced?

1 mole of propane = 4 moles of water

20 moles of propane = ( 4 * 20 ) moles of water

= 80 moles of water.

So, if 20 moles of propane were burned in excess oxygen, 80 moles of water will be formed. Propane is heavier than air and when properly combusted produces a large amount of heat. It is also non toxic.

6 0

3 years ago