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Alexeev081 [22]
3 years ago
7

Blue vitriol is commonly used in industrial dyeing processes. what is the chemical formula for blue vitriol, whose systematic na

me is copper(ii) sulfate? express your answer as a chemical formula.
Chemistry
1 answer:
Maslowich3 years ago
5 0
Answer is: chemical formula of blue vitriol is CuSO₄.
In this molecule copper has oxidation number +2 and sulfate has oxidation number -2, copper(II) sulfate has neutral charge (+2 +(-2) = 0).
Copper sulfate is produced industrially in chemical reaction of copper metal and hot concentrated <span>sulfuric acid.</span>
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According to the hypothesis the solar system formed from a cloud of dust and gas
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What is an example of inert elements​
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Suppose that 0.50 grams of barium-131 are administered orally to a patient. Approximately how many milligrams of the barium woul
nalin [4]

Two months later 13.8 milligrams of the barium-131 still be radioactive.

<h3>How is the decay rate of a radioactive substance expressed ? </h3>

It is expressed as:

A = A_{0} \times (\frac{1}{2})^{t/T}

where,

A = Amount remaining

A₀ = Initial Amount

t = time

T = Half life

Here

A₀ = 0.50g

t  = 2 months = 60 days

T = 11.6 days  

Now put the values in above expression we get

A = A_{0} \times (\frac{1}{2})^{t/T}

   = 0.50 \times (\frac{1}{2})^{60/11.6}

   = 0.50 \times (\frac{1}{2})^{5.17}

   = 0.50 × 0.0277

   = 0.0138 g

   = 13.8 mg          [1 mg = 1000 g]

Thus from the above conclusion we can say that Two months later 13.8 milligrams of the barium-131 still be radioactive.

Learn more about the Radioactive here: brainly.com/question/2320811

#SPJ1

Disclaimer: The question was given incomplete on the portal. Here is the complete question.

Question: Suppose that 0.50 grams of ban that 0.50 grams of barium-131 are administered orally to a patient. Approximately many milligrams of the barium would still be radioactive two months later? The half-life of barium-131 is 11.6 days.

3 0
1 year ago
C2d3 has a solubility product constant of 9.14×10−9. What is the molar solubility of c2d3?
shutvik [7]

Answer : The molar solubility of C_2d_3 is 9.67\times 10^{-3}M

Explanation :

The solubility equilibrium reaction will be:

C_2d_3\rightleftharpoons 2C^{3+}+3d^{2-}

The expression for solubility constant for this reaction will be,

Let the molar solubility be, 'x'

K_{sp}=(2x)^2\times (3x)^3

Now put all the given values in this expression, we get:

9.14\times 10^{-9}=108x^5

x=9.67\times 10^{-3}M

Therefore, the molar solubility of C_2d_3 is 9.67\times 10^{-3}M

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3 years ago
Describe three characteristics of the outer core and explain why the outer core is so important to humans on earth.
iren2701 [21]

Answer:

The outer core is the only layer that is liquid. It is also mainly made from nickel and iron. The main job of the outer core is that it's responsible for the Earth's magnetic field. As the earth spins, the liquid inside this layer spins aswell, keeping it balanced.

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