*WILL GIVE A BRAINIEST & 15 POINTS TO THE CORRECT ANSWER*

Why is powdered magnesium used in fireworks,<br>rather than magnesium ribbon?

blsea [12.9K]

Answer:

<em>Because it will give a faster reaction.</em>

Explanation:

3 0

3 years ago

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Data has been collected to show that at a given wavelength in a 1 cm pathlength cell, Beer's Law for the absorbance of Co2 is li

White raven [17]

Answer : The concentration of a solution with an absorbance of 0.420 is, 0.162 M

Explanation :

Using Beer-Lambert's law :

$A=\epsilon \times C\times l$

As per question, at constant path-length there is a direct relation between absorbance and concentration.

$\frac{A_1}{A_2}=\frac{C_1}{C_2}$

where,

A = absorbance of solution

C = concentration of solution

l = path length

$A_1$ = initial absorbance = 0.350

$A_2$ = final absorbance = 0.420

$C_1$ = initial concentration = 0.135 M

$C_2$ = final concentration = ?

Now put all the given value in the above relation, we get:

$\frac{0.350}{0.420}=\frac{0.135}{C_2}$

$C_2=0.162M$

Thus, the concentration of a solution with an absorbance of 0.420 is, 0.162 M

4 0

3 years ago

Refer to the following balanced equation in which ammonia reacts with nitrogen monoxide to produce nitrogen and water.

RSB [31]

Answer:4314

Explanation:

6 0

3 years ago

Which of the following most likely happens when the number of particles of a gas decreases?

Papessa [141]

Answer: C. The number of collisions of gas particles decreases

Explanation: As temperature decreases so does everything else same with increase.

3 0

3 years ago

A gaseous mixture of O2 and N2 contains 37.8% nitrogen by mass. What is the partial pressure of oxygen in the mixture if the tot

kondor19780726 [428]

Answer: The partial pressure of oxygen in the mixture if the total pressure is 525 mmHg is 310 mm Hg

Explanation:

mass of nitrogen = 37.8 g

mass of oxygen = (100-37.8) g = 62.2 g

Using the equation given by Raoult's law, we get:

$p_A=\chi_A\times P_T$

$p_{O_2}$ = partial pressure of $O_2$ = ?

$\chi_{O_2} = mole fraction of O_2=\frac{\text{Moles of }O_2}{\text{Total moles}}$

$P_{T}$ = total pressure of mixture = 525 mmHg

${\text{Moles of }O_2}=\frac{\text {Given mass}}{\text {Molar mass}}=\frac{62.2g}{32g/mol}=1.94moles$

${\text{Moles of }N_2}=\frac{\text {Given mass}}{\text {Molar mass}}=\frac{37.8g}{28g/mol}=1.35moles$

Total moles = 1.94 + 1.35 = 3.29 moles

$\chi_{O_2}=\frac{1.94}{3.29}=0.59$

$p_{O_2}=\chi_{O_2}\times P_T=0.59\times 525=310mmHg$

Thus the partial pressure of oxygen in the mixture if the total pressure is 525 mmHg is 310 mm Hg

7 0

3 years ago