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Schach [20]
3 years ago
6

PLEASE HELP!!! I am struggling

Mathematics
1 answer:
cestrela7 [59]3 years ago
4 0

The ball will be at height 19 feet first at 0.7 sec and then at 1.42 sec.

<u>Explanation:</u>

We need to find the time at which the ball will be at height 19 feet.

Equation:

h = 3 + 34t - 16t²

19 = 3 + 34t - 16t²

16 = -16t² + 34t

-16t² + 34t - 16 = 0

On solving the equation, we get

t1 = 0.7 s and t2 = 1.42s

Therefore, the ball will be at height 19 feet first at 0.7 sec and then at 1.42 sec.

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A sandbox has a perimeter of 21 1/2 feet. If the length is 5 1/4 feet, what is the area of the sand box?
LiRa [457]
The perimeter of a rectangle is twice the sum of length and width, so the sum of length and width is half the perimeter, 10 3/4 ft.

The width will be the difference between this and the length, hence 5 1/2 ft.

The area is the product of length and width.
  A = length×width
  A = (5.25 ft)×(5.5 ft) = 28.875 ft²

The area of the sandbox is 28 7/8 ft².
4 0
3 years ago
Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used. Consider the functions given below. SEE F
Wewaii [24]

Answer:

1. P(x) ÷ Q(x)---> \frac{-3x + 2}{3(3x - 1)}

2. P(x) + Q(x)---> \frac{2(6x - 1)}{(3x - 1)(-3x + 2)}

3.  P(x) - Q(x)---> \frac{-2(12x - 5)}{(3x - 1)(-3x + 2)}

4. P(x)*Q(x) --> \frac{12}{(3x - 1)(-3x + 2)}

Step-by-step explanation:

Given that:

1. P(x) = \frac{2}{3x - 1}

Q(x) = \frac{6}{-3x + 2}

Thus,

P(x) ÷ Q(x) = \frac{2}{3x - 1} ÷ \frac{6}{-3x + 2}

Flip the 2nd function, Q(x), upside down to change the process to multiplication.

\frac{2}{3x - 1}*\frac{-3x + 2}{6}

\frac{2(-3x + 2)}{6(3x - 1)}

= \frac{-3x + 2}{3(3x - 1)}

2. P(x) + Q(x) = \frac{2}{3x - 1} + \frac{6}{-3x + 2}

Make both expressions as a single fraction by finding, the common denominator, divide the common denominator by each denominator, and then multiply by the numerator. You'd have the following below:

\frac{2(-3x + 2) + 6(3x - 1)}{(3x - 1)(-3x + 2)}

\frac{-6x + 4 + 18x - 6}{(3x - 1)(-3x + 2)}

\frac{-6x + 18x + 4 - 6}{(3x - 1)(-3x + 2)}

\frac{12x - 2}{(3x - 1)(-3x + 2)}

= \frac{2(6x - 1}{(3x - 1)(-3x + 2)}

3. P(x) - Q(x) = \frac{2}{3x - 1} - \frac{6}{-3x + 2}

\frac{2(-3x + 2) - 6(3x - 1)}{(3x - 1)(-3x + 2)}

\frac{-6x + 4 - 18x + 6}{(3x - 1)(-3x + 2)}

\frac{-6x - 18x + 4 + 6}{(3x - 1)(-3x + 2)}

\frac{-24x + 10}{(3x - 1)(-3x + 2)}

= \frac{-2(12x - 5}{(3x - 1)(-3x + 2)}

4. P(x)*Q(x) = \frac{2}{3x - 1}* \frac{6}{-3x + 2}

P(x)*Q(x) = \frac{2*6}{(3x - 1)(-3x + 2)}

P(x)*Q(x) = \frac{12}{(3x - 1)(-3x + 2)}

4 0
3 years ago
amy borrows $130 to buy supplies for her birthday party. she receives gifts and money from her friends and family. the total amo
OLga [1]

Answer:

Step-by-step explanation:

If Amy received 250 dollars for her bday, but she borrowed before 130,

she will have left:

250-130=120 dollars

3 0
3 years ago
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3 0
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Is 499.50 great than or less than 499.05?
mote1985 [20]

Answer:

greater

Step-by-step explanation:

8 0
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