PLEASE HELP!!! I am struggling
1 answer:
The ball will be at height 19 feet first at 0.7 sec and then at 1.42 sec.
<u>Explanation:</u>
We need to find the time at which the ball will be at height 19 feet.
Equation:
h = 3 + 34t - 16t²
19 = 3 + 34t - 16t²
16 = -16t² + 34t
-16t² + 34t - 16 = 0
On solving the equation, we get
t1 = 0.7 s and t2 = 1.42s
Therefore, the ball will be at height 19 feet first at 0.7 sec and then at 1.42 sec.
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The answer is 5 and 2/5. Hopefully it is correct!
Answer:
1/2 km
Step-by-step explanation:
3/10 + 1/5, find common denominators
3/10 + 2/10 = 5/10, simplify
1/2 km
The equation would be 3l-5.