Answer:
the third one
Step-by-step explanation:
The diagonals of a rhombus are perpendicular bisectors of each other. You can use the Pythagorean theorem. If the diagonals are length "a" and "b", the side length of the rhombus (s) is
s = (1/2)√(a²+b²)
Took must make a 92 on the next test.
(81+84+84+69+76+x)/6=81
(394+x)/6=81
Multiply by 6 on both sides
394 + x = 486
Subtract 394 from both sides.
x= 92
<h3>
Answer: D) 0</h3>
Work Shown:
f(x) = 4x^(-2) + (1/4)x^2 + 4
f ' (x) = 4*(-2)x^(-3) + (1/4)*2x .... power rule
f ' (x) = -8x^(-3) + (1/2)x
f ' (2) = -8(2)^(-3) + (1/2)*(2)
f ' (2) = 0
Some rational numbers are
2.71, 2.72, 2.73, 2.74, 2.75, 2.76, 2.77, 2.78, 2.79
2.711, 2.712 2.713....
2.721, 2.722, 2.723....
2.731....
I think you get the point! Hope this helped!
