We conclude that the slope of the linear equation that passes through the points (9, 1) and (10, -1) is -2.
<h3>
How to get the slope of the line that passes through the points (9, 1) and (10, - 1)?</h3>
A linear equation has the general form:
y = a*x + b
Where a is the slope of the line, and b is the y-intercept.
There is a simple equation to get the slope of a point if we know two points. For a line that passes through ( a, b) and (c, d), the equation for the slope is:
a = (d - b)/(c - a)
In this case we know that our line passes through (9, 1) and (10, -1), then using the above equation, we can see that the slope is:
a = (-1 - 1)/(10 - 9) = -2
We conclude that the slope of the linear equation that passes through the points (9, 1) and (10, -1) is -2.
If you want to learn more about linear equations:
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Answer:
156 
Step-by-step explanation:
find the areas of all the faces and add them up
area of a rectangle: 
area of a trapezoid: 
the area of the trapezoid is multiplied by 2 because there's a top and bottom
Answer:
(
y
−
6
)
=
0
(
x
+
7
)
Explanation:
The point-slope formula states:
(
y
−
y
1
)
=
m
(
x
−
x
1
)
Where
m
is the slope and
(
x
1
y
1
)
is a point the line passes through.
Substituting the values from the equation gives:
(
y
−
6
)
=
0
(
x
−
−
7
)
(
y
−
6
)
=
0
(
x
+
7
)
Answer:
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Step-by-step explanation:
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